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3 years ago

Help me pls need help

Mathematics

2 answers:

alexira [117]3 years ago

7 0

Answer:

9s+11

Step-by-step explanation:

Combine like terms → (7s+2s and 2+9 = 9s and 11) and boom

otez555 [7]3 years ago

5 0

Answer:

$9s + 11$

Step-by-step explanation:

First:

$7s - 2s \\ = 9s$

second:

$9 + 2 \\ = 11$

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Answer:

A.) The first graph

Step-by-step explanation:

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3 years ago

a bank tellers hourly wage will increase from $24 to $27.60. what percent increase does this represent?a stereo is marked down $

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Step-by-step explanation:

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8 0

3 years ago

Solve for c; a/b+c=d/c

Eduardwww [97]

To solve for c, you need to get c onto one side of the equation, or make it c=__. So what I would do first is subtract a/b from both sides

a/b + c = d/c

-a/b

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8 0

3 years ago

Change the subject of the formula L = v 4kt - p to k.

Romashka [77]

Answer:

$\boxed{k = \frac{L^2 + p}{4t}}$

General Formulas and Concepts:

Algebra I

Basic Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle L = \sqrt{4kt - p}$

Step 2: Solve for k
We can use equality properties to help us rewrite the equation to get k as our subject:

Let's first square both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}$

Next, add p to both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}$

Next, divide 4t by both sides:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}$

We can rewrite the new equation by swapping sides to obtain our final expression:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}$

∴ we have changed the subject of the formula.

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Learn more about Algebra I: brainly.com/question/27698547

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Topic: Algebra I

6 0

2 years ago

Which two points satisfy y = -x2 2x 4 and x y = 4?

matrenka [14]

I will assume that the two equations are

1) y = -x^2 +2x + 4 and 2) x +y = 4

subtract 2 from 1 and you get

y -x - y = -x^2 + 2x + 4 - 4

-x = -x^2 +2x

x^2 -x -2x = 0

x^2 - 3x = 0

x(x-3)=0

x=0 and x - 3 =0

x=0 and x = 3

Then y = 4 - x

y = 4 - 0 and y = 4 -3
y = 4 and y =1

Solutions:

Points (0,4) and (3,1)

6 0

3 years ago