Answer: x=3
Step-by-step explanation:
To find the zeros, you want to first factor the expression.
x³+x²-36
(x-3)(x²+4x+12)
Now that we have found the factors, we set each to 0.
x-3=0
x=3
Since x²+4x+12 cannot be factored, we can forget about this part.
Therefore, the zeros are x=3. You can check this by plugging the expression into a graphing calculator to see the zeros.
<h2>
Answer:</h2>
This relation is a function because a function, in fact this is a linear function. We have that:
![\left[\begin{array}{cc}x & y\\2 & 3\\4 & 4\\6 & 5\\8 & 6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Dx%20%26%20y%5C%5C2%20%26%203%5C%5C4%20%26%204%5C%5C6%20%26%205%5C%5C8%20%26%206%5Cend%7Barray%7D%5Cright%5D)
As you can see below, all the points have been plotted an this is a linear function. Therefore, with two points we can get the equation, so:

Finally, the equation is:
