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Nostrana [21]
4 years ago
15

What makes the sentence true 1\2=?/12

Mathematics
1 answer:
bagirrra123 [75]4 years ago
6 0
It would be 1/2 = 6/12
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!!! CAN SOMEONE HELP !!! (PLEASE ILL GIVE BRAINLIST)
vladimir1956 [14]

Answer:

120 minutes

Step-by-step explanation:

the total bill was $58 so we have to subtract the $40 monthly bill part to find how much extra money she paid because her call was over 200 minutes

58-40=18

Then divide the $18 by $0.15 since the $18 is the total amount of each time she was charged $0.15 for going 1 minute over 200 minutes

18÷0.15 = 120

120 is te Amount Of minutes she went over her 200 minute limit

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3 years ago
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Left f(x)=|x| and g(x)=x+2. what are the domain and range of (f°g)(x)
mr_godi [17]

Answer:

(fog)(x)=|x+2|

Dom_{fog} = R

Range_{fog}=[0,\infty)

Step-by-step explanation:

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3 years ago
Please help work this out
BigorU [14]

Answer:

Area=190.091 cm^2

Step-by-step explanation:

Area = 1/2(Pi x r^2)    one-half because it's a semi-circle

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11^2=121 so, Area=1/2(3.14 x 121)

Area=1/2(379.94)

Area=189.97 cm^2

adjustment:

Area=1/2(3.142 x 11^2)

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3 years ago
The system of equations graphed below has how many solutions?
Artist 52 [7]
Answer: C) 0

The lines are parallel. They never cross. To have a solution, the lines need to intersect. Each intersection is a solution. That's why there are no solutions here. The system is inconsistent.

Note how the slopes are both 1/2 while the y intercepts are different. Parallel lines have equal slopes but different y intercepts.
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3 years ago
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Paraphin [41]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$50\\ r=rate\to 10\%\to \frac{10}{100}\dotfill &0.10\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

\bf A=50\left(1+\frac{0.10}{1}\right)^{1\cdot 2}\implies A=50(1.1)^2\implies A=60.5 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{earned interest}}{60.5 - 50\implies 10.5}~\hfill

7 0
3 years ago
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