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Julli [10]
3 years ago
13

There is a constant ratio between corresponding sides of similar figures. Since circles don't have sides, what ratio(s) could yo

u use to prove that all circles are similar?
Mathematics
2 answers:
inessss [21]3 years ago
7 0
A circle's size and shape is fully defined by its radius. Given two circles with radii r and r', the diameters are d=2r and d'=2r' and they are in the ratio 

<span>d'/d = (2r')/(2r) = r'/r. </span>

<span>The diameter ratio is the same as the radius ratio. Similarly, the circumferences c=πd and c' = πd' are in the ratio </span>

<span>c'/c = (πd')/(πd) = d'/d = r'/r </span>

<span>The circumference ratio is the same as the diameter ratio and the radius ratio. All of the key linear dimensions are in the same proportion. </span>

<span>You might point out that the same thing happens with a square, where the size and shape are also completely determined by a single measurement, the length s of a side, with the diagonal and perimeter (corresponding to diameter and circumference) being d = √2 s and p = 4s. </span>

<span>Maybe you can lead at least some of the students to generalize to other regular polygons. Some of them (like the equilateral triangle and regular hexagon) can be demonstrated like the square and circle above with formulas from geometry. The general case needs trig ratios to state the formulas relating side length to the radius and apothem of the polygon.</span>
hodyreva [135]3 years ago
5 0

Answer:

The ratio of circumference to diameter in all circles is a constant value, pi. Also, the ratio of the diameters and the ratio of the circumferences of any two circles reduces to the ratio of their radii.

Step-by-step explanation:

just answered question, answer above is what it said to be a possible answer

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Which ordred pair is in the solution set of 4x + 8y&gt;16 ?
ss7ja [257]

yes thats fab Step-by-step explanation:

The perimeter of a rectangle is 46 inches. If the width of the rectangle is 9 inches, what is the length?

A.  

23 inches

B.  

14 inches

C.  

28 inches

D.  

37 inches

Reset

6 0
2 years ago
Drag the tiles to the boxes to form correct pairs.
FrozenT [24]

Answer:

1 .4x2-9= 2x+3,2x-3

2 .16x2-1=4x-1,4x+1

3 .16x2-4=4(2x+1)(2x-1)

4 .4x2-1=(2x+1)(2x-1)

Step-by-step explanation:

16x² − 1  = (4x − 1)(4x + 1) ;  16x² − 4  = 4(2x + 1)(2x − 1); 4x² − 1  = (2x + 1)(2x − 1) ;

4x² − 9 = (2x + 3)(2x − 3)

16x² − 1  is the difference of squares.  This is because 16x² is a perfect square, as is 1.  To find the factors of the difference of squares, take the square root of each square; one factor will be the sum of these and the other will be the difference.

The square root of 16x² is 4x and the square root of 1 is 1; this gives us (4x-1)(4x+1).

16x² − 4 is also the difference of squares.  The difference of 16x² is 4x and the square root of 4 is 2; this gives us (4x-2)(4x+2).  However, we can also factor a 2 out of each of these binomials; this gives us

2(2x-1)(2)(2x+1) = 2(2)(2x-1)(2x+1) = 4(2x-1)(2x+1)

4x² − 1  is also the difference of squares.  The square root of 4x² is 2x and the square root of 1 is 1; this gives us (2x-1)(2x+1).

4x² − 9 is also the difference of squares.  The square root of 4x² is 2x and the square root of 9 is 3; this gives us (2x-3)(2x+3).

3 0
3 years ago
Please don’t just comment for points
masha68 [24]
1. no because 2x+10 is not equal to 2x+7
2. no. you cant add una like terms so 4x+4 doesn’t equal 8x
3. yes. the terms still retain their same value although they are not in the same order
4. yes. when u distribute the -3, you get -3x-6 which is of course equal to -3x-6
7 0
3 years ago
2x2x7x13<br> Write the number whose prime factorization is given
kramer

Answer:

364

Step-by-step explanation:

2x2x7x13

The prime factorization is just the factors of a number.

To find the number, multiply the numbers together

2*2 = 4

4*7 = 28

28*13 = 364

3 0
2 years ago
Read 2 more answers
Find the slope of each line <br> 9,4,-1,-6
marusya05 [52]

Answer: slope is 1

Step-by-step explanation:

-6-4= -10

-1-9 = -10

4 0
3 years ago
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