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navik [9.2K]
3 years ago
14

If justin has 90 tacos and loses 15 how many does he have

Mathematics
2 answers:
Ne4ueva [31]3 years ago
8 0

Answer:75

Step-by-step explanation:

90-15=75

Bumek [7]3 years ago
7 0

Answer:

He has 75 tacos left.

90 - 15 = 75.

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What is the product of 65(cos(14°)+ i sin(14°)) and 8(cos(4°)+ i sin(4°))
saveliy_v [14]

The product of the complex numbers 65(cos(14°)+ i sin(14°)) and 8(cos(4°)+ i sin(4°)) is 520[cos(18) + isin(18)]

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Complex number is in the form z = a + bi, where a and b are real numbers.

The product of the complex numbers 65(cos(14°)+ i sin(14°)) and 8(cos(4°)+ i sin(4°)) is:

z = 65 * 8 [cos(14 + 4) + isin(14 + 4)] = 520[cos(18) + isin(18)]

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Solve photo question. Mathematics. Please. Easy one. And last one.
Elan Coil [88]
A collection of nickels and dimes is worth $4.40. There are 53 coins in all. How many nickels are there?

Nickel is a US coin worth 5 cents or 0.05.
Dime is a US coin worth 10 cents or 0.10

n + d = 53
0.05n + 0.10d = 4.40

n = 53 - d
0.05(53 - d) + 0.10d = 4.40  
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0.05d = 4.40 - 2.65
0.05d = 1.75
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n = 53 - d
n = 53 - 35
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What is the circumference of a circle with a radius of eight inches
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Answer:

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\:

Step-by-step explanation:

It is given that, the radius of a circle is 8 inches and we are to find the circumference of the circle.

\:

To find the circumference of the circle we must know this formula first :

\\{ \longrightarrow \qquad{ \underline {\boxed{ \pmb{ \mathfrak{  \: Circumference_{(circle)}= 2 \pi r}}}}}} \: \: \bigstar \\ \\

Where

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  • We'll take the value of π as 3.14

Now substituting the values in the formula :

\\{ \longrightarrow \qquad{  {{\sf{{  \: Circumference_{(circle)}= 2  \times 3.14 \times  8}}}}}} \: \:  \\ \\

{ \longrightarrow \qquad{  {{\sf{{  \: Circumference_{(circle)}=    3.14 \times  16}}}}}} \: \:  \\ \\

{ \longrightarrow \qquad{  { \pmb{\frak{{  \: Circumference_{(circle)}=    50.24}}}}}} \: \:  \\ \\

Therefore,

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