A = $2,861.60
I = A - P = $2,361.60
Equation:
A = P(1 + rt)
Calculation:
First, converting R percent to r a decimal
r = R/100 = 26.24%/100 = 0.2624 per year.
Solving our equation:
A = 500(1 + (0.2624 × 18)) = 2861.6
A = $2,861.60
The total amount accrued, principal plus interest, from simple interest on a principal of $500.00 at a rate of 26.24% per year for 18 years is $2,861.60.
Answer:
Step-by-step explanation:
The second set. It contains (2,2) and (2,7), so it fails the vertical-line test.
Answer:
Juanita borrowed $600 to purchase a computer
Step-by-step explanation:
Grammer
Answer:
-x+5
Step-by-step explanation:
5-5x+4x
= 5+(-5x)+4x
combine like terms:
5+(-5x)+4x
(-5x+4x)+(5)
= -x+5
9514 1404 393
Answer:
$2.50
Step-by-step explanation:
The question asks for the total cost of a notebook and pen together. We don't need to find their individual costs in order to answer the question.
Sometimes we get bored solving systems of equations in the usual ways. For this question, let's try this.
The first equation has one more notebook than pens. The second equation has 4 more notebooks than pens. If we subtract 4 times the first equation from the second, we should have equal numbers of notebooks and pens.
(8n +4p) -4(3n +2p) = (16.00) -4(6.50)
-4n -4p = -10.00 . . . . . . . . . . . simplify
n + p = -10.00/-4 = 2.50 . . . . divide by the coefficient of (n+p)
The total cost for one notebook and one pen is $2.50.
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<em>Additional comment</em>
The first equation has 1 more notebook than 2 (n+p) combinations, telling us that a notebook costs $6.50 -2(2.50) = $1.50. Then the pen is $2.50 -1.50 = $1.00.
One could solve for the costs of a notebook (n) and a pen (p) individually, then add them together to answer the question. We judge that to be more work.
