Answer:2
Step-by-step explanation:
I don't know how your teacher chooses to solve this problem (or your text) but I do it this way.
Divide 81 by 3. You get 27.
Use 27 as your middle integer and go one odd integer up and down for the other 2.
25, 27, 29
the largest would be 29.
This works because 3 of the middle number equals 81, so the middle number plus a number 2 greater and a number 2 less would still be the same as adding 3 of the same number.
Check by adding the 3 numbers.
25 + 27 + 29 = 81
Answer:
the two positive consecutive integers are 4 and 6.
Step-by-step explanation:
Let the smaller integer be s; then s^2 = (s + 2) + 10.
Simplifying, s^2 - s - 2 - 10 = 0, or
s^2 - s - 12 = 0.
Solve this by factoring: (s - 4)(s + 3) = 0.
Then s = 4 and s = -3.
If the first even integer is 4, the next is 6. We omit s = -3 because it's not even.
The smaller integer is 4. Does this satisfy the equation s^2 = (s + 2) + 10?
4^2 = (4 + 2) + 10 True or False?
16 = 6 + 10 = 16.
True.
So the two positive consecutive integers are 4 and 6.
I believe the answer is 1/216
