Determine the graph of the sinusoid with amplitude of 4 and period of 2π/3
1 answer:
Answer:
Option b.
y = 4 sin (3x)
Step-by-step explanation:
To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.
Please see the attached image below, to find more information about the graph
The period is
T = 2π/3
This means the frequency in radians is
W = 2π/T = 3
The equation is either:
y = 4 cos(3x)
y = 4 sin (3x)
The correct answer is
Option b.
y = 4 sin (3x)
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Answer:
x = 13
Step-by-step explanation:
Given that Δ NML and Δ PST are similar right triangles, we can set up the following proportional statement to establish their relationship:
Cross multiply:
8(x + 2) = 10 (x - 1)
8x + 16 = 10x - 10
Subtract 8x from both sides:
8x - 8x + 16 = 10x - 8x - 10
16 = 2x - 10
Add 10 to both sides:
16 + 10 = 2x - 10 + 10
26 = 2x
Divide both sides by 2:
13 = x
Verify whether x = 13 is the correct value:
This shows the proportional relationship between , and that ΔNML and ΔPST are indeed similar right triangles.
Therefore, the correct answer is x = 13.