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Anettt [7]
3 years ago
13

I need the quadratic formula.

Mathematics
1 answer:
Gre4nikov [31]3 years ago
3 0
ax²+bx+c=0
4a²x²+4abx+4ac=0
4a²x²+4abx=-4ac
4a²x²+4abx+b²=b²-4ac
(2ax+b)²=b²-4ac
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PLEASE HELP ME IN MATH IM CONFUSED
Butoxors [25]

Answer:

the second choice is correct

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{3}{4} x - 9 is in this form

with slope m = \frac{3}{4}

• Parallel lines have equal slopes, hence

y = \frac{3}{4} x + c ← is the partial equation of the parallel line

To find c substitute (- 8, - 18) into the partial equation

- 18 = - 6 + c ⇒ c = - 18 + 6 = - 12

y = \frac{3}{4} x - 12 ← equation of parallel line



4 0
3 years ago
1) f(x)=(x - 3)(x - 5)
NemiM [27]

Answer:

Step-by-step explanation:

f(x)= (x - 3)(x - 5)

f(x) = x^2 - 5x - 3x + 15

f(x) = x^2 - 8x + 15

Answer is A

7 0
2 years ago
A triangle has a 90° angle. What type of triangle is it?
CaHeK987 [17]

Answer:

Its a right triangle

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
If f(x)=3x^2-5 and g(x)=-2x+5, then f(3)g(3)=
Vladimir [108]

Answer:

(

f

+

g

)

(

x

)

=

3

x

2

+

x

+

2

Explanation:

(

f

+

g

)

(

x

)

=

f

(

x

)

+

g

(

x

)

:

(

f

+

g

)

(

x

)

=

3

x

2

−

x

+

5

+

2

x

−

3

Add like terms:

(

f

+

g

)

(

x

)

=

3

x

2

+

(

−

x

+

2

x

)

+

(

5

−

3

)

(

f

+

g

)

(

x

)

=

3

x

2

+

x

+

2

(

f

+

g

)

(

x

)

=

3

x

2

+

x

+

2

Explanation:

(

f

+

g

)

(

x

)

=

f

(

x

)

+

g

(

x

)

:

(

f

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g

)

(

x

)

=

3

x

2

−

x

+

5

+

2

x

−

3

Add like terms:

(

f

+

g

)

(

x

)

=

3

x

2

+

(

−

x

+

2

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)

+

(

5

−

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)

(

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g

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(

x

)

=

3

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2

+

x

+

2

(

f

+

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(

x

)

=

3

x

2

+

x

+

2

Explanation:

(

f

+

g

)

(

x

)

=

f

(

x

)

+

g

(

x

)

:

(

f

+

g

)

(

x

)

=

3

x

2

−

x

+

5

+

2

x

−

3

Add like terms:

(

f

+

g

)

(

x

)

=

3

x

2

+

(

−

x

+

2

x

)

+

(

5

−

3

)

(

f

+

g

)

(

x

)

=

3

x

2

+

x

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Step-by-step explanation:

5 0
2 years ago
Find the area of the largest rectangle (with sides parallel to the coordinate axes) that can be inscribed in the region enclosed
garik1379 [7]
F(x) = 18-x^2 is a parabola having vertex at (0, 18) and opening downwards. 
g(x) = 2x^2-9 is a parabola having vertex at (0, -9) and opening upwards. 
By symmetry, let the x-coordinates of the vertices of rectangle be x and -x => its width is 2x. 
Height of the rectangle is y1 + y2, where y1 is the y-coordinate of the vertex on the parabola f and y2 is that of g.
 => Area, A 
= 2x (y1 - y2) 
= 2x (18 - x^2 - 2x^2 + 9) 
= 2x (27 - 3x^2) 
= 54x - 6x^3 
For area to be maximum, dA/dx = 0 and d²A/dx² < 0 
=> 54 - 18x^2 = 0 
=> x = √3 (note: x = - √3 gives the x-coordinate of vertex in second and third quadrants) 

d²A/dx² = - 36x < 0 for x = √3 
=> maximum area 
= 54(√3) - 6(√3)^3 
= 54√3 - 18√3 
= 36√3. 
4 0
2 years ago
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