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Crazy boy [7]
3 years ago
9

The system of equations below represents the measures of 2 angles created by the diagonal of a rectangle: x + y = 90 y =1/5 What

is the measure of the greater angle? ° What is the measure of the smaller angle? °
Mathematics
1 answer:
madreJ [45]3 years ago
4 0

Answer:

The larger of the two angles is x, which is 75. y is the smaller angle at 15.

Step-by-step explanation:

In order to find these, we can use our solved value for y in the second equation to plug into the first equation. This method is called substitution.

x + y = 90

x + (1/5x) = 90

1.2x = 90

x = 75

Now we can plug that value into either equation to find y

y = 1/5x

y = 1/5(75)

y = 15

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Step-by-step explanation:

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Aleks04 [339]
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8 0
2 years ago
Describe and correct the error in solving the equation<br><br> 7 - 3x = 12<br> 4x = 12<br> x = 3
aev [14]
If x=3
Just replace the X with 3
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3 0
2 years ago
Suppose m = 2 + 6i, and | m + n | = 3√10, where n is a complex number.
Ksju [112]

Answer: a) √50

b) n = 1 + 7i

Step-by-step explanation:

first, the modulus of a complex number z = a + bi is

IzI = √(a^2 + b^2)  

The fact that n is complex does not mean that n doesn't has a real part, so we must write our numbers as:

m = 2 + 6i

n = a  + bi

Im + nI = 3√10

Im + n I = √(a^2 + b^2 + 2^2 + 6^2)= 3√10

            = √(a^2 + b^2 + 40) = 3√10

             a^2 + b^2 + 40 = 3^2*10 = 9*10 = 90

             a^2 + b^2 = 90 - 40 = 50

            √(a^2 + b^2 ) = InI = √50

The modulus of n must be equal to the square root of 50.

now we can find any values a and b such a^2 + b^2 = 50.

for example, a = 1 and b = 7

1^2 + 7^2 = 1 + 49  = 50

Then a possible value for n is:

n = 1 + 7i

6 0
3 years ago
Find the​ fourth-degree polynomial function with zeros 4​, -4, 4i ​, and -4i . Write the function in factored form.
Iteru [2.4K]

Given:

A fourth-degree polynomial function has zeros 4​, -4, 4i ​, and -4i .

To find:

The fourth-degree polynomial  function in factored form.

Solution:

The factor for of nth degree polynomial is:

P(x)=(x-a_1)(x-a_2)...(x-a_n)

Where, a_1,a_2,...,a_n are n zeros of the polynomial.

It is given that a fourth-degree polynomial function has zeros 4​, -4, 4i ​, and -4i. So, the factor form of given polynomial is:

P(x)=(x-4)(x-(-4))(x-4i)(x-(-4i))

P(x)=(x-4)(x+4)(x-4i)(x+4i)

P(x)=(x-4)(x+4)(x^2-(4i)^2)           [\because a^2-b^2=(a-b)(a+b)]

On further simplification, we get

P(x)=(x-4)(x+4)(x^2-4^2i^2)

P(x)=(x-4)(x+4)(x^2+16)                [\because i^2=-1]

Therefore, the required fourth degree polynomial is P(x)=(x-4)(x+4)(x^2+16).

6 0
2 years ago
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