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Ksivusya [100]
4 years ago
14

At which direction does less than or = 4 go to

Mathematics
1 answer:
ivanzaharov [21]4 years ago
5 0
< with the line underneath
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Please help and THANK YOU
Sonja [21]

Answer:

no problem

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Hello people ~
fiasKO [112]

Hey there!

Complementary angles add up to 90 degrees.

We are given

An angle of 79 degrees

and we're asked to find the complement of the angle.

So let's set up an equation:

79+x=90

where x=the unknown angle

Subtract 79 from both sides:

79-79+x=90-79

x=11

Hence, the measure of the unknown angle is

\boxed{\boxed{\bold{11}}}

Hope everything is clear.

Let me know if you have any questions!

#LearningIsFun

\rule{200}{2}

4 0
2 years ago
Read 2 more answers
Evaluate the following question <br> PLZ
kozerog [31]

Answer:

1599995904

Step-by-step explanation:

first, you must do the top part of the fraction. you can start by doing the power numbers such as 2 power 4, 4 power 6 and 4 power 4.

the complete answer for the top part is: 12x 16x 4069x 8x 2x 256 which equals: 3199991808

then, you must divide by 2 which gives you the answer of: 1599995904

8 0
3 years ago
What is 3.276 x 10^9 in standard form?
Delicious77 [7]

The exponent is a positive number, so you move the decimal point, that many places to the right:

3.276 x 10^9 = 3,276,000,000

7 0
3 years ago
Two part-time instructors are hired by the Department of Statistics and each is assigned at random to teach a single course in p
scZoUnD [109]

Answer:

The probability that they will teach different courses is \frac{2}{3}.

Step-by-step explanation:

Sample space is a set of all possible outcomes of an experiment.

In this case we will write the sample space in the form (x, y).

Here <em>x</em> represents the course taught by the first part-time instructor and <em>y</em> represents the course taught by the second part-time instructor.

Denote every course by their first letter.

The sample space is as follows:

S = {(P, P), (P, I), (P, S), (I, P), (I, I), (I, S), (S, P), (S, I) and (S, S)}

The outcomes where the the instructors will teach different courses are:

s = {(P, I), (P, S), (I, P),(I, S), (S, P) and (S, I)}

The probability of an events <em>E</em> is the ratio of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Compute the probability that they will teach different courses as follows:

P(\text{Different courses})=\frac{n(s)}{n(S)}=\frac{6}{9}=\frac{2}{3}

Thus, the probability that they will teach different courses is \frac{2}{3}.

3 0
3 years ago
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