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3 years ago

13

Write the equation of the line in slope intercept form equation of the line in slope intercept form is blank

1 answer:

Slav-nsk [51]3 years ago

4 0

Answer:

y=70x+20

Step-by-step explanation:

Okay so the slope is determined by having two points on the line in this case one of them is (0,20) and (2,160), you're going 140 up and 2 over so the slope would be $\frac{140}{2}$ which equals 70 so thats how you get m, to get b you simply put the y interecept which is at 20.

Plugs those numbers together you get y=70x+20 which is intercept form.

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Consider the triangle. Which shows the order of the angles from smallest to largest? angle A, angle B, angle C angle B, angle A,

Katyanochek1 [597]

Answer:

angle B, angle A, angle C

Step-by-step explanation:

The shortest side length will be opposite the smallest angle, and the longest side length will be opposite the largest angle.

When the triangle is drawn and labeled, we see that AB is opposite angle C; BC is opposite angle A; and CA is opposite angle B.

Since the smallest side is AC, this means the smallest angle is angle B.

Since the middle length side is BC, the middle sized angle is A.

Since the longest side is AB, the largest angle is C.

This means the order from smallest to largest is B, A, C.

6 0

3 years ago

Read 2 more answers

HELP ME PLSSSSS I NEED HELP PLS PLS PLS ITS PYTHAGOREAN THEOREM

sergij07 [2.7K]

H=9ft
B=6ft

Using Pythagorean thereon

$\\ \Large\sf\longmapsto P^2=H^2-B^2$

$\\ \Large\sf\longmapsto P^2=9^2-6^2$

$\\ \Large\sf\longmapsto P^2=81-36$

$\\ \Large\sf\longmapsto P^2=45$

$\\ \Large\sf\longmapsto P=\sqrt{45}$

$\\ \Large\sf\longmapsto P=6.3ft$

7 0

3 years ago

A 5 foot tall student casts a shadow that is 8 feet long. A 12.5 foot flag pole close by casts a shadow with an unknown length,

prohojiy [21]

Answer:

15.5

Step-by-step explanation:

3 0

3 years ago

Help please with this question.

Tanzania [10]

2x+3(x+1.5)=12 because y=y so you SUBSTITUTE y in for y

6 0

3 years ago

Find the number of steel ball bearings, each of diameter 0.7 cm, that can be made from 1kg of steel, given that 1cm cubed of ste

dimulka [17.4K]

Answer:

Ball Bearing Volume = (4 / 3) * PI * radius ^3

Volume = (4 / 3) * 3.14159265 * (.35)^3

Volume = (4 / 3) * 3.14159265 * 0.042875

Volume = 0.17959438 cc

1 cc of steel = 7.8 g

Volume of 1 kg of steel = 1,000 cc / 7.8 g per cc

1 kg = 128.205 cc

Number of ball bearings we can make = 128.205 / 0.17959438

Equals 713.86

Step-by-step explanation:

7 0

4 years ago