All categories

3 years ago

In right triangle QRS, Angle S is a right angle, QS = 33, SR = 56, and QR = 65. What is

Mathematics

1 answer:

posledela3 years ago

3 0

The value of sine of angle Q is 1.16

Explanation:

Given:

ΔQRS is a right angle triangle

∠S = 90°

QS = 33

SR = 56

QR = 65

Sin(∠Q) = ?

We know:

$sin \alpha = \frac{perpendicular}{hypotenuse}$

So,

$sin(Q) = \frac{QR}{RS} \\\\Sin (Q) = \frac{65}{56} \\\\sin (Q) = 1.16$

Therefore, the value of sine of angle Q is 1.16

You might be interested in

Monique is factoring the expression 4 x + 16 x y. Her work is shown below. Factors of 4x: 1, 2, 4, x Factors of 16xy: 1, 2, 4, 8

Anika [276]

Answer:

Monique made an error when writing the factored expression.

Correct factored

expression=4x(1+4y)

Step-by-step explanation:

factoring the expression 4 x + 16 x y.

Factors of 4x: 1, 2, 4, x

Factors of 16xy: 1, 2, 4, 8, 16, x, y

GCF: 4x

Factored expression: 4 x (0 + 4 y)

Monique made an error when writing the factored expression.

The correct factored expression should be:

4x+16xy

=4x(1+4y)

Contrary to 4x(0+4y)

Correct factored

expression=4x(1+4y)

4 0

3 years ago

Read 2 more answers

M A. 59 B. 31 C. 149 D. 62

lbvjy [14]

I think The answer is a.59

4 0

4 years ago

A mountain climber ascended 3/4 of a kilometer in 1/12 of an hour. What was the mountain climber’s ascent rate in kilometers per

Yanka [14]

A mountain climber ascended 3/4 of a kilometer in 1/12 of an hour. What was the mountain climber’s ascent rate in kilometers per hour?

Correct Answer: C. 9 Kilometers per hour

3 0

3 years ago

Read 2 more answers

For the month of March in a certain city, 57% of the days are cloudy. Also in the month of March in the same city, 55% of the da

oksian1 [2.3K]

Answer: 0.9649

Step-by-step explanation:

Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.

Given : For the month of March in a certain city, the probability that days are cloudy : $P(A)=0.57$

Also in the month of March in the same city,, the probability that the days are cloudy and rainy : $P(A\cap B)=0.55$

Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-

$P(B|A)=\dfrac{P(A\cap B)}{P(A)}$

$\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}$

Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649

4 0

4 years ago

What is 0.051369 tounded to the nearest hundredths Answer quick!

NNADVOKAT [17]

I think it’s 0.05,,,,,

3 0

3 years ago