Answer:
1/6
Step-by-step explanation:
out of 6 numbers in total there is only one 6 therefore there is only 1/6 chances
Answer:
r = -5
Step-by-step explanation:
-11 = 1+3r+3
-11 = 3r + 4
3r = -15
r = -5
Calculate the probability that both bids are successful
Answer:
The probability that both contracs are successful is 0.21
Step-by-step explanation:
Given
E1 = the event that the bid on the first contract is successful
E2 = the event that the bid on the second contract is successful
P(E1) = 0.3
P(E2) = 0.7
Let P(A) represent the event that both contracts are successful
P(A) = P(E1 and E2)
Since both events are independent. P(A) becomes
P(A) = = P(E1 * P(E2)
By substituton
P(A) = 0.3 * 0.7
P(A) = 0.21
Hence the probability that both contracs are successful is 0.21
