Answer:
See below :)
Step-by-step explanation:
The easiest way to graph this is to find the x-intercept and y-intercept,
y-intercept:
The y-intercept is extremely easy to find as it's just the "b" in "y = mx + b"
If there is no b, it's (0,0). If there is a b, its (0,b)
This is because the y-intercept is where the lines hits the y-axis so we know x must be 0. We can plug in x as 0 to find y:
y = m(0) + b
y = b
In this case, the y-intercept is (0,3) because the b in y = -8/3x + 3
x-intercept:
The x-intercept requires a little more work. It's the same as the y-intercept. The x-intercept is where the lines hits the x-axis so we know y must be 0. The x-intercept is (x,0)
We can use this to plug in y as 0:
0 = mx + b
mx = -b
Now we use this to find the the x-intercept:
0 = -8/3x + 3
8/3x = 3
Divide both sides by 8/3:
x = 3 * 3/8
x = 9/8
In this case, the x-intercept is (9/8,0)
Now we can use these points and connect a line to them and then the lines keeps going forever. Look at the picture I uploaded :)
Answer:
sdjcbdsljvbdsjkvbsdkjv
Step-by-step explanation:

<u>First Train:</u>
Time taken = 9 hours (2pm to 11pm)
Let the speed be x
Distance = Time x Speed = 9x
<u>Second Train:</u>
Time taken = 5 hours (6pm to 11pm)
Speed = x + 48
Distance = Time x Speed = 5(x + 48)
Since both the distance they traveled are the same, we equate the distance to solve for x.
<u>Solve for x:</u>
9x = 5(x + 48)
9x = 5x + 240
4x = 240
x = 60
<u>Find the speed:</u>
x = 60 mph
x + 48= 108 mph
Answer: The spend of the two trains are 60 mph and 108 mph.
Answer:
b = 2A/h - a . (option a)
Step-by-step explanation:
Check attachment