Solve by elimination.
The goal is to cancel out one of the variables in order to easily solve for the other variable.
Do this by changing the equations so that the coefficients of either x or y add up to 0.
Notice the coefficients of y are 3 and 3, if we make one of them negative then they add up to 0. 3+ (-3) = 0
Multiply 2nd equation by -1.
6x +3y = 9
-2x -3y = -1
__________
4x +0y = 8
Solve for x
4x = 8
x = 8/4 = 2
Plug x=2 back into one of original equations to find y.
---> 2(2) + 3y = 1
---> 4 + 3y = 1
---> 3y = -3
---> y = -1
Therefore solution is (2,-1)
Answer:
If there are 1000 customers in the store one week, how many will purchase exactly one of these items
1000 CUSTOMERS*28%=280
Step-by-step explanation:
A The event that a persons buys a suit
B The event that a person buys a shirt
C The event that a person buys a tie
P(A)= 22%
P(B)= 30%
P(C)= 28%
P(AB)=
11%
P(AC)=
14%
P(BC)=
10%
P(ABC)=
6%
A u B u C Is the event that any item is bougth
AC u AC u BC Is the event that any two events occured
So the wanted probability is
P[(A u B u C )(AB u AC u BC)^c
P[(A u B u C )=P(AB)+ P(BC)+P(BC)
P[(A u B u C ) =0.22+0.30+0.28-0.11-0.14.-0.10+0.06
=0,51
0,51=+0,23+P[(A u B u C )(AB u AC u BC)^c
=0,28
1000 CUSTOMERS*28%=280
Step-by-step explanation:
6|8-y|-15
6|8-10|-15
6|-2|-15
6(2)-15
12-15
-3
Not too sure but i think it’s D
