Burrito: 20
hot sauce: 80
taco: 400
Answer:
Yes they will intersect
Function 1= F(X)=2X+5
Function 2=H(X)=3X+2
INTERSECT=(3,11)
Step-by-step explanation:
First of all, we create 2 LINEAR function, i created the function f(x)=2x+5 and the function h(x)=3x+2, both are linear(without a quadratic term). Then
you replace the x for a number:
Table 1 (F(X)=2X+5) Table 2 (H(X)=3X+2)
X=1----->Y=2+5=7 X=1------>Y=3·1+2=5
X=2---->Y=2·2+5=9 X=2----->Y=3·2+2=8
X=3---->Y=3·3+5=11 X=3----->Y=3·3+2=11
With both tables of data we can see that in the X=3/Y=11 point this two linear functions will intersect so the answer is that the two functions will intersect at (3,11)----->(X,Y)
Answer:
2 real solutions
Step-by-step explanation:
Get all the terms to one side
10n^2 = 10 - 8n
10n^2 +8n -10 =0
ax^2 +bx+c =0
The discriminant is
b^2 -4ac
8^2 - 4(10)(-10)
64 +400
464
If the discriminant is greater than 0 we have 2 real solutions
Answer: 30 degrees
Step-by-step explanation: Vertical angles are always congruent. If Angle A and Angle B are vertical then they are equal to each other. They both will way thirty degrees.
