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Serhud [2]
3 years ago
7

The function g(x)=x^2+3. The f(x)=g(x+2)

Mathematics
1 answer:
vekshin13 years ago
4 0

Answer:

f(x)=x^2+6x+12

Step-by-step explanation:

Given:

The function 'g(x)' is given as:

g(x)=x^2+3

Now, the function 'f(x)' is given as:

f(x)=g(x+2)

So, the function 'f(x)' is a transformation of 'g(x)'.

In order to find f(x), we replace 'x' by (x + 2) in the 'g(x)' function equation. This gives,

g(x+2)=(x+2)^2+3

Using the identity (a+b)^2=a^2+b^2+2ab, we get:

g(x+2)=x^2+3^2+6x+3\\\\g(x+2)=x^2+9+6x+3\\\\g(x+2)=x^2+6x+12

Hence the function f(x) is given as:

f(x)=x^2+6x+12

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For which function is f(x) equal to f^1(x) ( answer choices in picture )
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Answer:

C. f(x)=\frac{x+1}{x-1}

Step-by-step explanation:

Let's find the inverse of each of the given options.

Option A:

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To find f^{-1}(x), replace 'x' with 'y' and 'y' with 'x'. This gives,

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Rewrite in terms of 'y'. This gives,

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The given function y=\frac{6x+6}{x-1}\ne y=\frac{x+6}{x-6}

So, option A is incorrect.

Option B:

f(x)=\frac{x+2}{x-2}\\y=\frac{x+2}{x-2}

To find f^{-1}(x), replace 'x' with 'y' and 'y' with 'x'. This gives,

x=\frac{y+2}{y-2}

Rewrite in terms of 'y'. This gives,

x(y-2)=y+2\\xy-2x=y+2\\xy-y=2x+2\\y=\frac{2x+2}{x-1}

The given function y=\frac{2x+2}{x-1}\ne y=\frac{x+2}{x-2}

So, option B is incorrect.

Option C:

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Rewrite in terms of 'y'. This gives,

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The given function y=\frac{x+1}{x-1}\ equals\ y=\frac{x+1}{x-1}

So, option C is correct.

Option D:

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To find f^{-1}(x), replace 'x' with 'y' and 'y' with 'x'. This gives,

x=\frac{y+5}{y-5}

Rewrite in terms of 'y'. This gives,

x(y-5)=y+5\\xy-5x=y+5\\xy-y=5x+5\\y=\frac{5x+5}{x-1}

The given function y=\frac{5x+5}{x-1}\ne y=\frac{x+6}{x-6}

So, option D is incorrect.

Therefore, only option C is correct.

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