How do you solve a Complex Volume problem?

What is the angle relationship?

dsp73

Answer:

i think vertical

Step-by-step explanation:

it is a vertical line at the bottom

7 0

3 years ago

during a test of a totalizing flow meter, the water depth rose 15 inches in a tank 18 inches in diameter. What was the total flo

sattari [20]

Answer:

The total flow in gallons is approximately 16.524 gallons

Step-by-step explanation:

The given diameter of the tank, D = 18 inches

The amount by which the water depth rose, Δh = 15 inches

The quantity being measured = The total flow = The change in volume of water in the tank

The change in the volume of the water in the tank, ΔV = (π × D²/4) × Δh

Substituting the known values, gives;

ΔV = (π × D²/4) × Δh = (π × (18 in.)²/4) × (15 in.) ≈ 3817.035 in.³

1 gallon = 231 in.³

ΔV ≈ 3817.035 in.³ = 3817.035 in.³ × 1 gallon/(231 in.³) ≈ 16.524 gallons

The change in the volume of the water in the tank, ΔV in gallons = The total flow in gallons ≈ 16.524 gallons.

4 0

3 years ago

What is the solution set to the inequality (4x-3)(2x-1)20?

Fynjy0 [20]

The given question is wrong.

Question:

What is the solution set to the inequality (4x – 3) (2x – 1) ≥ 0?

(A) $\{x| x\leq 3\ \text {or} \ x\geq 1$

(B) $\{x| x\leq 2\ \text {or} \ x\geq \frac{4}{3}$

(C) $\{x| x\leq \frac{1}{2}\ \text {or} \ x\geq \frac{3}{4}$

(D) $\{x| x\leq \frac{-1}{2}\ \text {or} \ x\geq \frac{-3}{4}$

Answer:

The solution set to the given inequality is $\{x| x\leq \frac{1}{2}\ \text {or} \ x\geq \frac{3}{4}$ .

Solution:

Given expression is (4x – 3) (2x – 1) ≥ 0.

Let us take the expression is equal to zero.

(4x – 3) (2x – 1) = 0

By quadratic factor, If AB = 0, then A = 0 or B = 0.

(4x – 3) = 0 or (2x – 1) = 0

Let us take the first factor equal to zero.

⇒ 4x – 3 = 0

⇒ 4x = 3

$$x=\frac{3}{4}$

Now, take the second factor equal to zero.

⇒ 2x – 1 = 0

⇒ 2x = 1

$$x=\frac{1}{2}$

So, $$x=\frac{1}{2},x=\frac{3}{4}$ .

Now, write it in the inequality to make the statement true.

$$x\geq \frac{1}{2}\ \text{(or)}\ x\leq \frac{3}{4}$

Option C is the correct answer.

The solution set to the given inequality is $\{x| x\leq \frac{1}{2}\ \text {or} \ x\geq \frac{3}{4}$ .

6 0

4 years ago

Simplify the question. 1/4g plus 6g minus 2/3

MatroZZZ [7]

1/4+6-2/3
3/12+72/12-8/12
75/12-8/12
67/12
or
.25+6-.66
6.25-.66
5.59

3 0

3 years ago

5X+17=7 PLEASE HELP FAST

BARSIC [14]

Answer:

-2

Step-by-step explanation:

8 0

3 years ago

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