Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
24:14 and 36:21 are both equivalent ratios to 12:7
Answer:
b
Step-by-step explanation:
to find the answer to this you sould divide the amount of pints by the number of bottles
18/8
which is also 2 2/8
so the answer is b
Answer:
L = 29.6 cm
Step-by-step explanation:
Let Length be L and Breadth be B
<u><em>Condition 1:</em></u>
Where Perimeter = 296 cm
=> 2L + 2B = 296
=> 2(L+B) = 296
<em>Dividing both sides by 2</em>
=> L + B = 148 ------------------(1)
<u><em>Condition 2:</em></u>
=> B = 
-------------------------(2)
Putting Equation 2 in 1
=> L + = 148
Multiplying both sides by 3
=> 3L + 2L = 148
=> 5L = 148
=> L = 148/5
=> L = 29.6 cm
Answer:
12 mph
Step-by-step explanation:
The relationship between jogging speed and walking speed means the time it takes to walk 4 miles is the same as the time it takes to jog 8 miles. Then the total travel time (0.75 h) is the time it would take to jog 1+8 = 9 miles. The jogging speed is ...
(9 mi)(.75 h) = 12 mi/h . . . average jogging speed
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<em>Check</em>
1 mile will take (1 mi)/(12 mi/h) = 1/12 h to jog.
4 miles will take (4 mi)/(6 mi/h) = 4/6 = 8/12 h to walk.
The total travel time is (1/12 +8/12) h = 9/12 h = 3/4 h. (answer checks OK)
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<em>Comment on the problem</em>
Olympic race-walking speed is on the order of 7.7 mi/h, so John's walking speed of 6 mi/h should be considered quite a bit faster than normal. The fastest marathon ever run is on the order of a bit more than 12 mi/h, so John's jogging speed is also quite a bit faster than normal. No wonder he got tired.
