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ivolga24 [154]
3 years ago
9

Can someone please help me quickly

Mathematics
1 answer:
tia_tia [17]3 years ago
6 0
1. The amount will remain the same because 1/8*8/1*x=1x
2. 15*5280/3600=ft per second
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Coffee sells for $5 per pound. If a farmer sells 12,000,000 pounds of coffee, how much money will the farmer make?
lana [24]

Answer:

8939459577232

Step-by-step explanation:

yeah

4 0
3 years ago
Read 2 more answers
I really need help with this my deadline is very soon​
Harman [31]

Answer:

(3)\ y = -x

(5)\ y = -3x -2

Step-by-step explanation:

Required

The equation in slope intercept form

Solving (3):

m = -1

(x_1,y_1) =(4,-4)

The equation in slope intercept form is:

y = m(x - x_1) + y_1

This gives:

y = -1(x - 4) -4

Expand

y = -x + 4 -4

y = -x

Solving (5):

m = -3

(x_1,y_1) = (1,-5)

The equation in slope intercept form is:

y = m(x - x_1) + y_1

This gives:

y = -3(x - 1) - 5

Expand

y = -3x + 3 - 5

y = -3x -2

8 0
2 years ago
S 8,000 a good estimate for the sum of 3,816 and 467?
Damm [24]

Answer:

it is  not a good estimate.

Step-by-step explanation:3816 can be rounded to 4000 and 467 can be rounded to 500. Adding 4000+500 gives 4500, which isn't near 8000.

i hoped this helped :)

<3

7 0
3 years ago
Jacob made a circle-shaped poster for his geometry class.
krok68 [10]
<span>circumference is L=2\pi r
L=2π9=18π=18*3.14=56.52 in
Answer:  </span>circumference is <span>18π or 56.52 in</span>
5 0
3 years ago
Points M, N, and P are respectively the midpoints of sides AC , BC , and AB of △ABC. Prove that the area of △MNP is on fourth of
Hunter-Best [27]

Answer:

The area of △MNP is one fourth of the area of △ABC.

Step-by-step explanation:

It is given that the points M, N, and P are the midpoints of sides AC, BC and AB respectively. It means AC, BC and AB are median of the triangle ABC.

Median divides the area of a triangle in two equal parts.

Since the points M, N, and P are the midpoints of sides AC, BC and AB respectively, therefore MN, NP and MP are midsegments of the triangle.

Midsegments are the line segment which are connecting the midpoints of tro sides and parallel to third side. According to midpoint theorem the length of midsegment is half of length of third side.

Since MN, NP and MP are midsegments of the triangle, therefore the length of these sides are half of AB, AC and BC respectively. In triangle ABC and MNP corresponding side are proportional.

\triangle ABC \sim \triangle NMP

MP\parallel BC

MP=\frac{BC}{2}

By the property of similar triangles,

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{PM^2}{BC^2}

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{(\frac{BC}{2})^2}{BC^2}

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{1}{4}

Hence proved.

5 0
3 years ago
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