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ivolga24 [154]
3 years ago
9

Can someone please help me quickly

Mathematics
1 answer:
tia_tia [17]3 years ago
6 0
1. The amount will remain the same because 1/8*8/1*x=1x
2. 15*5280/3600=ft per second
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Secants BE and CF intersect at point D inside A. What is the measure of CDE?
Aleks04 [339]
MCE = 360 - (150 + 70 + 50)
mCE = 360 - 270
mCE = 90

<CDE = 1/2(mBE + mCE)
<CDE = 1/2(150 + 90)
<CDE = 1/2(240)
<CDE = 120

answer
<CDE = 120°
6 0
3 years ago
Officer Brimberry wrote 16 tickets for traffic violations last week, but only 2 tickets this week. What is the percent decrease?
Verdich [7]

Answer:

87.5%

Step-by-step explanation:

It decreased by 16 - 2 or 14, and since he wrote 16 tickets last week, the answer is 14/16 in percent form, or 7/8 = 87.5%.

6 0
3 years ago
Sqrt(2x-6)=3-x<br> Solve for x
soldi70 [24.7K]

Answer:

x = 3

Step-by-step explanation:

\sqrt{2x - 6}  = 3 - x

Square both sides of the equation

2x - 6 = (3 - x)^{2} = 9 - 6x + x^{2} \\

x^{2}  - 8x + 15 = 0\\

(x - 3)(x - 5) = 0

x = 3 or 5

Now, you must always check your results because a result may not satisfy the original equation.

If x = 3, then \sqrt{2x - 6} = \sqrt{2(3) - 6} = \sqrt{6 - 6}  = \sqrt{0} = 0  and 3 - x = 3 - 3 = 0

So 3 satisfies the original.

If x = 5, then \sqrt{2(5) - 6}  = \sqrt{10 - 6} = \sqrt{4} = 2,  but 3 - x = 3 - 5 = -2.  Therefore, 5 does NOT satisfy the original equation.

That means that x = 3 is the solution to the equation.

5 0
2 years ago
A car rental agency has 150 cars. The owner finds that at a price of $48 per day, he can rent all the cars. For each $2 increase
hram777 [196]
Given that for each <span>$2 increase in price, the demand is less and 4 fewer cars are rented.

Let x be the number of $2 increases in price, then the revenue from renting cars is given by
(48 + 2x) \times (150 - 4x)=7,200+108x-8x^2.

Also, given that f</span><span>or each car that is rented, there are routine maintenance costs of $5 per day, then the total cost of renting cars is given by
5(150-4x)=750-20x

Profit is given by revenue - cost.
Thus, the profit from renting cars is given by
</span><span>(7,200+108x-8x^2)-(750-20x)=6,450+128x-8x^2

For maximum profit, the differentiation of the profit function equals zero.
i.e.
</span><span>\frac{d}{dx} (6,450+128x-8x^2)=0 \\  \\ 128-16x=0 \\  \\ x= \frac{128}{16} =8

The price of renting a car is given by 48 + 2x = 48 + 2(8) = 48 + 16 = 64.

Therefore, the </span><span>rental charge will maximize profit is $64.</span>
3 0
3 years ago
What should be multiplied with -25/36 to get -5/9​
Ierofanga [76]

Answer:

\frac{4}{5}

Step-by-step explanation:

\frac{-\frac{5}{9}}{-\frac{25}{36}}=\\\\-\frac{5}{9}*(-\frac{36}{25})=\\\\\frac{4}{5}

6 0
2 years ago
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