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Ymorist [56]
4 years ago
13

What’s an adjacent angle

Mathematics
1 answer:
ICE Princess25 [194]4 years ago
7 0
Two angles are adjacent when they have a common side and a common vertex (corner point) and don't overlap.

Hope this helped!

(Found this on a website)
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Which expression is equivalent to -6(-2/3+2x) <br> -4-12x<br> -4+2x <br> 4-12x<br> 4+12x
Basile [38]
C. Is your answer to the question
4 0
3 years ago
Read 2 more answers
10 more than a number divided by -8
Effectus [21]

Answer:

6X8=48 10 more is 58

Step-by-step explanation:

6 0
3 years ago
Easy question and easy point <br><br><br> what is 2+2-2+6*8
oksian1 [2.3K]
The answer is 46 thank you
7 0
3 years ago
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Find the output, kkk, when the input, ttt, is -7−7minus, 7.<br> k = 10t-19k=10t−19
Sati [7]

The output k at input t = -7 is -89

Step-by-step explanation:

In order to find the value of a expression on given number, we put the number in given expression in place of independent variable

So,

Given expression is:

k = 10t-19

It is given that the value of t has to be -7

so putting t=-7 in the expression

k = 10(-7)-19\\k = -70-19\\k = -89

Hence,

The output k at input t = -7 is -89

Keywords: Expressions, input, output

Learn more about expressions at:

  • brainly.com/question/9723881
  • brainly.com/question/9720317

#LearnwithBrainly

8 0
3 years ago
Read 2 more answers
Which of the following is an improper integral?
guapka [62]

Answer:

A)  \displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx

General Formulas and Concepts:

<u>Calculus</u>

Discontinuities

  • Removable (Hole)
  • Jump
  • Infinite (Asymptote)

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C
  • Improper Integrals

Step-by-step explanation:

Let's define our answer choices:

A)  \displaystyle \int\limits^3_0 {\frac{x + 1}{3x - 2}} \, dx

B)  \displaystyle \int\limits^3_1 {\frac{x + 1}{3x - 2}} \, dx

C)  \displaystyle \int\limits^0_{-1} {\frac{x + 1}{3x - 2}} \, dx

D) None of these

We can see that we would have a infinite discontinuity if x = 2/3, as it would make the denominator 0 and we cannot divide by 0. Therefore, any interval that includes the value 2/3 would have to be rewritten and evaluated as an improper integral.

Of all the answer choices, we can see that A's bounds of integration (interval) includes x = 2/3.

∴ our answer is A.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Integration

Book: College Calculus 10e

6 0
3 years ago
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