All categories

3 years ago

PLEASE HELP ME WHAT AM I SUPPOSE TO DO?!

Mathematics

1 answer:

stepladder [879]3 years ago

8 0

Answer:

Step-by-step explanation:

Angle 2= 50

angle 1= 180-50= 130 degrees (linear pair (sum 180))

angle 3= 130 degrees (vertically oposite angles are equal)

angle 6= 130 degrees (alternate interior angles)

angle 5= 180-130= 50 degrees (linear pair)

i hope this helps :)

You might be interested in

Kameron has 9 video games at his house. This is half as many games as Kevin has. Write an equation that demonstrates the relatio

Illusion [34]

Answer:

The answer is 18

Step-by-step explanation: Because 9 + 9 = 18 so therefore Kameron and Kevin has 27 video game in total :/

6 0

4 years ago

the senior class has 225 members. there are 55 more boys in the class than girls. how many boys and girls are there

Natasha_Volkova [10]

Answer:

85 girls and 140 boys

Step-by-step explanation:

6 0

3 years ago

What is the sign of -4-8

dusya [7]

Answer:

The sign should be negative ( - )!

Step-by-step explanation:

-4 - 8 = -12

Please mark Brainliest!!! =D

7 0

3 years ago

Use sigma notation to represent the sum of the first six terms of the following sequence: −10, −13, −16, …

SSSSS [86.1K]

Sigma notation of sequence −10, −13, −16, … is $\sum_{n=1}^{6}-(3 n+7)$

<h3>Solution:</h3>

Need to determine the sigma notation for the following sequence

−10, −13, −16, …

Let's try to build a generic formula for given sequence

The given sequence is in Arithmetic progression where first term = -10 and common difference = -3

The formula for arithmetic progression is given as:

$a_n = a_1 + (n - 1)d$

Where,

$a_n$ is the nth term in the sequence

$a_1$ is the first term in the sequence

d is the common difference between the terms

Here in this sequence $a_1$ = -10 and d = -3

$a_n = -10 + (n - 1)(-3)\\\\a_n = -10 - 3n + 3\\\\a_n = -3n - 7$

So generic formula for a term is – ( 3n + 7 )

$\begin{array}{l}{\text { For } \mathrm{n}=1, \text { term is }-(3 \times 1+7)=-10} \\\\ {\text { For } \mathrm{n}=2, \text { term is }-(3 \times 2+7)=-13} \\\\ {\text { For } \mathrm{n}=3, \text { term is }-(3 \times 3+7)=-16}\end{array}$

And so on

Using sigma notation for arithmetic sequence:

$\sum_{k=1}^{n} a_{k}$

So for first six terms value of n will vary from 1 to 6 and in sigma notation it can be represented as

$\sum_{n=1}^{6}-(3 n+7)$

3 0

3 years ago

X+y-2z=-9 2x-y+8z=99 x-2y+5z=23 give the solution with z arbitrary

AveGali [126]

Answer:

(x, y, z) = (-4, 29, 17)

Step-by-step explanation:

These three equations have a unique solution. If you want "z arbitrary", you need to write a system of two equations with three variables (or, equivalently, a set of dependent equations).

It is convenient to let a graphing calculator, scientific calculator, or web site solve these.

_____

You can reduce the system to two equations in y and z by ...

subtracting the last equation from the first:

3y -7z = -32

subtracting twice the last equation from the second:

3y -2z = 53

Subtracting the first of these from the second, you get ...

5z = 85

z = 17

The remaining variable values fall out:

y = (53+2z)/3 = 87/3 = 29

x = -9 +2z -y = -9 +2(17) -29 = -4

These equations have the solution (x, y, z) = (-4, 29, 17).

3 0

4 years ago