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irga5000 [103]
3 years ago
11

Four more than 3 times a number is 31. Find that number

Mathematics
2 answers:
SpyIntel [72]3 years ago
7 0

Answer:9

Step-by-step explanation: 31-4=27

27÷3=9

nikitadnepr [17]3 years ago
5 0

Answer:

Step-by-step explanation:

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Select the statements that are true based on the following given information. D = {x | x is a whole number} E = {x | x is a perf
likoan [24]
<h3>2 Answers: Choice C and Choice D</h3>

==========================================================

Explanation:

Let's write the roster notation of each set

D = {0, 1, 2, 3, ...} the dots indicate the pattern goes on forever

E = {0, 1, 4, 9, 16, 25} = list of perfect squares smaller than 36

F = {20, 22, 24, 26, 28, 30} = even numbers between 20 and 30

----------------

If we intersect sets D and E, we're looking for what numbers are in both sets at the same time. Therefore, D ∩ E = {0, 1, 4, 9, 16, 25} which is the exact same as set E. This is because all of set E is inside of set D. We say that set E is a subset of set D. So, D ∩ E = E.

Choice A is very close to being true. The problem is that 25 is missing from the set {1,4,9,16}. So this is why choice A is false.

----------------

Now let's intersect sets D and F. The numbers they have in common are {20, 22, 24, 26, 28, 30} which is exactly what set F is. So set F is a subset of set D. We can write D ∩ F = F in much the same way we can say D ∩ E = E.

D ∩ F = {12,14,16,18} is not true. A number like 12 is not between 20 and 30, so it cannot be in set F.

Choice B is false so we cross it off the list.

----------------

Choice C is true and here's why

D ∪ (E ∩ F) is the same as saying D ∪ G where G is the set of intersecting E and F together. In other words, G = E ∩ F

We don't really need to even worry about sets E, F or G. All that matters here is set D.

When we write D ∪ (E ∩ F) or D ∪ G, we're saying "a number is in set D, or it is in set G". If it is in D, then it's a whole number. Otherwise, it's in a subset of whole numbers.

Overall, D ∪ G and D ∪ (E ∩ F) form the entire set of whole numbers.

------------------

Choice D is true.

E and F have nothing in common

E = {0, 1, 4, 9, 16, 25}

F = {20, 22, 24, 26, 28, 30}

So intersecting them leads to the empty set. This is the set with nothing inside it, not even 0.

------------------

Choice F is false

These two sets below

E = {0, 1, 4, 9, 16, 25}

F = {20, 22, 24, 26, 28, 30}

union together to get

H = {0,1,4,9,16,20,22,24,25,26,28,30}

just toss all of the numbers together into one big set

Notice how each of these numbers are whole numbers, so they are part of set D. This means set H is also a subset of set D.

When we intersect sets D and H, we end up with set H. We do not simply end up with the set with 25 only inside it.

6 0
3 years ago
How do you simplify the radical √144 ?
SVETLANKA909090 [29]

Answer:

its 12

Step-by-step explanation:

you find whats closest for example, 10 squared is 100.

100 is close to 144

and 11x11= 121

so you would do 12

12x12 is 144

8 0
3 years ago
Read 2 more answers
Two parralel lines are cut by a transveral what is the measure of 8
dexar [7]

Answer:

its B... i think(sub2pewdiepie)

Step-by-step explanation:angle 4 is 100 degrees and 4 and 8 are corresponding

8 0
2 years ago
Read 2 more answers
How do I graph 2d + 4p = 28
gayaneshka [121]
I hope this helps you! Have a great day! :)

7 0
2 years ago
Hlol can u plz solve b no plz plz.....I will mark as brainliest​
zimovet [89]

Answer:

Step-by-step explanation:

Tan \ B =\frac{4}{3} = \frac{opposite \ side \ of B}{adjacent \ side \ of B}

BC = 15 cm

3x = 15

x = 15/3 = 5

AB =4x = 4*5 = 20 cm

Pythagorean theorem,

AC² = AB² + BC²

       = 20²  + 15 ²

       = 400 + 225

       = 625

AC = √625 = 25 cm

AC = 25 cm

Sin \ A = \frac{opposite  \ side \ of \ angle A }{hypotenuse}\\\\  = \frac{BC}{AB}=\frac{15}{25}=\frac{3}{5}

6 0
3 years ago
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