All categories

3 years ago

N x 6/9 = 3/12 what is N?

1 answer:

4 0

1

Simplify n\times \frac{6}{9}n×96 to \frac{2n}{3}32n

\frac{2n}{3}=\frac{3}{12}32n=123

2

Simplify \frac{3}{12}123 to \frac{1}{4}41

\frac{2n}{3}=\frac{1}{4}32n=41

3

Multiply both sides by 33

2n=\frac{1}{4}\times 32n=41×3

4

Simplify \frac{1}{4}\times 341×3 to \frac{3}{4}43

2n=\frac{3}{4}2n=43

5

Divide both sides by 22

n=\frac{\frac{3}{4}}{2}n=243

6

Simplify \frac{\frac{3}{4}}{2}243 to \frac{3}{4\times 2}4×23

n=\frac{3}{4\times 2}n=4×23

7

Simplify 4\times 24×2 to 88

n=\frac{3}{8}n=83

You might be interested in

Need help pleaseeeeeeeeeeeeeeee

Sonbull [250]

Answer:

good night sweet dreams take care

please Mark me as a<u> </u><u>BRINLIEST</u>

6 0

3 years ago

A scientist claims that 7% 7 % of viruses are airborne. If the scientist is accurate, what is the probability that the proportio

Reptile [31]

Answer:

The probability is $P(|p-\^{p}| > 0.03) = 0.0040$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.07$

The mean of the sampling distribution is $\mu_p = 0.07$

The sample size is n = 600

Generally the standard deviation is mathematically represented as

$\sigma_p = \sqrt{\frac{p (1 -p)}{n} }$

=> $\sigma_p = \sqrt{\frac{0.07(1 -0.07)}{600} }$

=> $\sigma_p = 0.010416$

Generally the probability that the proportion of airborne viruses in a sample of 600 viruses would differ from the population proportion by greater than 3% is mathematically represented as

$P(|p-\^{p}| > 0.03) = 1 - P(|p -\^{p}| \le 0.03)$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-0.03 \le p -\^{p} \le 0.03 )$

Now add p to both side of the inequality

=> $P(|p-\^{p}| > 0.03) = 1 - P( 0.07-0.03 \le \^{p} \le 0.03+ 0.07 )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(0.04 \le \^{p} \le 0.10 )$

Now converting the probabilities to their respective standardized score

=> $P(|p-\^{p}| > 0.03) = 1 - P(\frac{0.04 - 0.07}{0.010416} \le Z \le \frac{0.10 -0.07}{0.010416} )$

=> $P(|p-\^{p}| > 0.03) = 1 - P(-2.88 \le Z \le 2.88 )$

=> $P(|p-\^{p}| > 0.03) = 1 - [P(Z \le 2.88) - P(Z \le -2.88)]$

From the z-table

$P(Z \le 2.88) = 0.9980$

and

$P(Z \le -2.88) = 0.0020$

$P(|p-\^{p}| > 0.03) = 1 - [0.9980 - 0.0020]$

=> $P(|p-\^{p}| > 0.03) = 0.0040$

7 0

3 years ago

HELP ME NO RANDOM ANSWERS

ruslelena [56]

Answer: A

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A choir is performing in front of an audience. a microphone is placed in front of the choir to capture sound. which polar equati

viktelen [127]

The polar equation is r = 2 + cos(theta).

Given,

A choir is performing in front of an audience. a microphone is placed in front of the choir to capture sound.

The polar equation represents the microphone the choir is using i.e

On edge i.e r = 2 + cos(theta)

Hence, The polar equation is r = 2 + cos(theta).

Learn more about polar equations here brainly.com/question/23575937

#SPJ4

3 0

2 years ago

When is a parallelogram is a rhombus ?

Ierofanga [76]

A parallelogram is a rhombus when one of the following conditions is done:
1. All sides of the parallelogram are equal to each other.
2. The diagonals of the parallelogram intersect at a right angle (90°).
3. The diagonals of the parallelogram are the bisectors of its angles.

I hope this helps.

3 0

4 years ago

Read 2 more answers