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3 years ago

N x 6/9 = 3/12 what is N?

1 answer:

4 0

1

Simplify n\times \frac{6}{9}n×96 to \frac{2n}{3}32n

\frac{2n}{3}=\frac{3}{12}32n=123

2

Simplify \frac{3}{12}123 to \frac{1}{4}41

\frac{2n}{3}=\frac{1}{4}32n=41

3

Multiply both sides by 33

2n=\frac{1}{4}\times 32n=41×3

4

Simplify \frac{1}{4}\times 341×3 to \frac{3}{4}43

2n=\frac{3}{4}2n=43

5

Divide both sides by 22

n=\frac{\frac{3}{4}}{2}n=243

6

Simplify \frac{\frac{3}{4}}{2}243 to \frac{3}{4\times 2}4×23

n=\frac{3}{4\times 2}n=4×23

7

Simplify 4\times 24×2 to 88

n=\frac{3}{8}n=83

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Nemos aquarium is filled with 2400 cm of water the base of the aquarium is 20 cm long and 12 cm wide what is the height of the w

SSSSS [86.1K]

The answer to this question is 10 cm

In this question, you asked the height and given the volume of water(2400cm3), aquarium length(20cm), and aquarium width(12cm).

Then you need to divide the volume with the length and width. The equation would be:

Aquarium height= volume / length / width

Aquarium height= 2400 cm3 / 20cm / 12 cm = 10cm.

7 0

3 years ago

Using f(X)=x+2 and g(x)=10x-4 , what is f(2) + g(4) ?

Ksivusya [100]

F(2)+g(4)
evaluate them seperately
f(2)=2+2=4

g(4)=10(4)-4
g(4)=40-4
g(4)=36

f(2)+g(4)=4+36=40

3 0

4 years ago

What are the values of x and y

kaheart [24]

Answer:

x = 10, y = 12

Step-by-step explanation:

There is a 2:1 ratio between 16 and 8, alternate side lengths.

2x = 20

x = 10

2(6) = y

y = 12

5 0

3 years ago

Read 2 more answers

Two trains left the cities A and B at the same time and headed towards each other. The cities are s miles apart. The first train

Alona [7]

Answer:

t = $\frac {s}{(v_{1} + v_{2})}$ -------------(1)

The value of t is, $2\dfrac {1}{2}$ hour

Step-by-step explanation:

The 1st train travels at $v_{1}$ mph whereas the 2nd train travels at

$v_{2}$ mph. The trains are headed towards each other. They are s miles apart. In 1 hour their distance is reduced by $(v_{1} + v_{2})$ mile

So, in t hour their distance is reduced by $(v_{1} + v_{2}) \times t$ mile.

Now if the two trains meet after t hour of starting, then,

$(v_{1} + v_{2}) \times t = s$

⇒ t = $\frac {s}{(v_{1} + v_{2})}$ -------------(1)

If s = 250 unit, $v_{1}$ = 60 unit and, $v_{2}$ = 40 unit , then,

from (1), t = (250/(60 + 40)) hour = $2\dfrac {1}{2}$ hour ----(2)

5 0

4 years ago

Segments AB , CD , and EF intersect at point O, points A, E, C and points B, F, D are collinear so that AO ≅ OB , CO ≅ OD . Prov

katovenus [111]

If points A, E and C are colinear, then they lie on the same line. The same statement you can say about points B, F and D.

1. Consider triangles AOC and BOD. In these triangles:

AO≅OB (given);
CO≅OD (given);
∠AOC≅∠BOD (as vertical angles).

Thus, ΔAOC≅ΔBOD by SAS Postulate (If any two corresponding sides and their included angle are the same in both triangles, then the triangles are congruent). Corresponding parts of congruent triangles are congruent, then

AC≅BD;
∠ACO≅∠BDO;
∠CAO≅∠DBO.

Since angles ACO and BDO are alternate interior angles between lines AE and BF with transversal CD and these angles are congruent, then lines AE and BF are parallel.

This gives you that

∠CEO≅∠OFD;
∠ECO≅∠ODF.

2. Consider triangles ECO and FDO. In these triangles

∠CEO≅∠OFD (previous proof);
CO≅OD (given);
∠ECO≅∠ODF (previous proof).

Therefore, ΔECO≅ΔFDO by AAS Postulate (if two angles and the non-included side one triangle are congruent to two angles and the non-included side of another triangle, then these two triangles are congruent). Then CE≅FD.

3. Note that

AE=AC+CE;
BF=BD+DF.

Since AC≅BD and CE≅DF, then AE=AC+CE=BD+DF=BF.

7 0

3 years ago