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svetoff [14.1K]
3 years ago
5

It is a SQL keyword that creates an autoincrementing field.

Computers and Technology
1 answer:
Serjik [45]3 years ago
6 0

Answer:

c. AUTO_INCREMENT

Explanation:

this should help

You might be interested in
Dr. Watson has been kidnaped! Sherlock Holmes was contacted by the kidnapper for ransom. Moments later he received a message fro
adelina 88 [10]

Answer:

please mark me brainlist

Explanation:

This algorithm works for n number of strings in python3

Input:

83217

8213897

683147

Output:

837

from itertools import product

import pdb

import numpy as np

def neigh(index):

N = len(index)

for ri in product((0, -1), repeat=N):

if not all(i == 0 for i in ri):

yield tuple(i + i_rel for i, i_rel in zip(index, ri))

def longestCommonSubSequenceOfN(sqs):

numberOfSequences = len(sqs); # to know number of sequences

lengths = np.array([len(sequence) for sequence in sqs]); # to know length of each sequences placed in # array

incrLengths = lengths + 1; # here we are taking no .of sequences +1

lengths = tuple(lengths); # making lengths into tuple to make it mutable

inverseDistances = np.zeros(incrLengths);

ranges = [tuple(range(1, length+1)) for length in lengths[::-1]]; # finding ranges from 1 to each lengths

for tupleIndex in product(*ranges):

tupleIndex = tupleIndex[::-1];

neighborIndexes = list(neigh(tupleIndex)); # finding neighbours for each tupled index value and # store them in list

operationsWithMisMatch = np.array([]); # creating array which are miss matched

 

for neighborIndex in neighborIndexes:

operationsWithMisMatch = np.append(operationsWithMisMatch, inverseDistances[neighborIndex]);

#appending newly created array with operations miss match and inverseDistances

operationsWithMatch = np.copy(operationsWithMisMatch);

# copying newly generated missmatch indexs

operationsWithMatch[-1] = operationsWithMatch[-1] + 1;

# incrementing last indexed value

chars = [sqs[i][neighborIndexes[-1][i]] for i in range(numberOfSequences)];

# finding a string(chars) with neighbour indexes and checking with other sequences

if(all(elem == chars[0] for elem in chars)):

inverseDistances[tupleIndex] = max(operationsWithMatch);

else:

inverseDistances[tupleIndex] = max(operationsWithMisMatch);

 

subString = ""; # resulted string

mainTupleIndex = lengths; # copying lengths list to mainTupleIndex

while(all(ind > 0 for ind in mainTupleIndex)):

neighborsIndexes = list(neigh(mainTupleIndex));

#generating neighbour indexes with main tuple index in form of list

anyOperation = False;

for tupleIndex in neighborsIndexes:

current = inverseDistances[mainTupleIndex];

if(current == inverseDistances[tupleIndex]): # comparing indexes in main tuple index and inverse #distance tuple index

mainTupleIndex = tupleIndex;

anyOperation = True;

break;

if(not anyOperation): # if anyoperation is False then we are generating sunString

subString += str(sqs[0][mainTupleIndex[0] - 1]);

mainTupleIndex = neighborsIndexes[-1];

return subString[::-1]; # reversing resulted string

sequences = ["83217", "8213897", "683147"]

print(longestCommonSubSequenceOfN(sequences)); #837

8 0
3 years ago
Create a class named Horse that contains the following data fields: name - of type String color - of type String birthYear - of
kozerog [31]

Answer:

The program to this question can be given as:

Program:

class Horse   //define class Horse

{  

private String name;   //define variables.

private String color;  

private int birthYear;  

//define set method.

public void setName(String name)  

{  

this.name = name; //set value of name.

}

public void setColor(String color)  

{  

this.color = color; //set value of color.  

}  

public void setBirthYear(int birthYear)

{  

this.birthYear = birthYear;  //set value of birthYear

}  

//define get method.

public String getName()  

{  

return name;  //return name.

}  

public String getColor()

{  

return color;  //return color.

}  

public int getBirthYear()

{  

return birthYear;  //return birthYear.

}  

}

class RaceHorse extends Horse     //define class RaceHorse  

{

private String raceNum;            //define variable.

public void setRace(String raceNum)    //define set method.

{

 this.raceNum=raceNum;      //set value of raceNum.

}

public String getRace()

{

 return raceNum;   //return raceNum

}

}

public class Main      //define main class.

{

public static void main(String[] args) //define main method.

{

 Horse ob= new Horse();  //creating class objects.

 RaceHorse ob1 = new RaceHorse();

 ob.setName("XXX");       //calling function

 ob.setColor("BLACK");

 ob.setBirthYear(2008);

 ob1.setRace("Five hundred meter");

 //print return values.

       System.out.println("The name of the horse is " + ob.getName()+"." +"\n"+  

   "The horse's color is " + ob.getColor()+"."+"\n"+ "It was born in " + ob.getBirthYear() +  

   "."+"\n"+ ob.getName()+" has taken part in " + ob1.getRace() + " races.");

   

}

}

Output:

The name of the horse is XXX.

The horse's color is BLACK.

It was born in 2008.

XXX has taken part in Five hundred meter races.

Explanation:

In the above program firstly we declare the class that is Horse in this class we define a variable that name is already given in the question which are name, color, and birthYear. In these variables are name and color datatype is string and the birthYear datatype is an integer because it stores the number. Then we use the get and set function in the get function we return all variable value. and in the set function, we set the values of the variable by this keyword. Then we declare another class that is RaceHorse this class inherit Horse class. In the RaceHorse class, we define a variable that is raceNum that's data type is a string in this class we also used the get and set function. Then we declare the main class in the main class we define the main method in the main method we create the above class object and call the set and get function and print the values of the function.

6 0
4 years ago
Int main() { printf("%d\n", getOddPositionedDigits(89201)); printf("%d\n", getOddPositionedDigits(-123)); printf("%d\n", getOddP
Luba_88 [7]

Int Main () dvaunoax o]inxoo jnjn os'i

Explanation: Int Main KIcqvd[uo v[ionon

hxbc ;zzzzzzzzzzzczjHiuhqvzbp;'k

3 0
3 years ago
Gwen has a photo she'd like to display in her speech, but she forgot to digitize it. She only has a hard copy, and she doesn't h
irina1246 [14]

Answer:

Option(d) i.e "document camera " is the correct answer for the given question  

Explanation:

The document camera is mainly preferable when our aim displays the object into a large audience with the help of document camera  Gwen displays her speech into the classroom.

The hard copy is simply placed in the document camera, it takes the hard copy as an image format and gives the live image of the speech with the help of a monitor .

  • The main advantage of a document camera is that they provide greater flexibility.
  • Traditional whiteboard, overhead projector, flip charts not the best solution for that problem also they do not provide flexibility so they are all incorrect options.

8 0
4 years ago
Dogs are great pets for families because they teach children many important life lessons. (2) A dog must be walked and fed at ce
PIT_PIT [208]

The answer is A on edge. A)Just like homework and other activities, helping to take care of a dog teaches a child about responsibility.

4 0
3 years ago
Read 2 more answers
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