Question

What is the missing constant term in the perfect square that starts with x^2 - 16x ?

Answer 1

ANSWER

The missing constant term is 64

EXPLANATION

The given expression is

${x}^{2} - 16x$

Let the k be the constant term, then

${x}^{2} - 16x + k$

is a perfect square.

This implies that, the discriminant is zero.

The discriminant is

$D= {b}^{2} - 4ac$

${( - 16)}^{2} - 4(1)(k) = 0$

$256 - 4k = 0$

$- 4k = - 256$

$k = \frac{ - 256}{ - 4}$

$k = 64$

Answer 2

Answer:

64 pleb

Step-by-step explanation: