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hoa [83]
3 years ago
5

What is the missing constant term in the perfect square that starts with x^2 - 16x ?

Mathematics
2 answers:
RideAnS [48]3 years ago
8 0

ANSWER

The missing constant term is 64

EXPLANATION

The given expression is

{x}^{2}  - 16x

Let the k be the constant term, then

{x}^{2}  - 16x + k

is a perfect square.

This implies that, the discriminant is zero.

The discriminant is

D= {b}^{2}  - 4ac

{( - 16)}^{2}  - 4(1)(k) = 0

256 - 4k = 0

- 4k =  - 256

k =  \frac{ - 256}{ - 4}

k = 64

mamaluj [8]3 years ago
5 0

Answer:

64 pleb

Step-by-step explanation:

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