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4 years ago

Solve. 90x = 27. Explain every step. Full credit will not be earned unless each step is explained.

Mathematics

2 answers:

alexira [117]4 years ago

5 0

Answer: x= 0.3 or x=3/10

Step-by-step explanation:

90x=27

divide both sides by 90

x=27/90 which simplfiyes to 3/10

x=0.3

maw [93]4 years ago

4 0

90x = 27

1) 90x = 27 | :90 [divide by 90 to get our x]

2) x = 27/90 [simplify by 3]

3) x = 7/30 [ our x is equal that]

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Use substitution to solve the system. -3x+ 5y = 22 x = 37-14 x 6 ?

DaniilM [7]

Answer:

y=18.2

Step-by-step explanation:

-3x+5y=22

-3(37-14)+5y=22

-69+5y=22

5y=91

y=18.2

check:

-3(37-14)+5(18.2)=22

-69+91=22

22=22

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3 years ago

The number of telephone calls that arrive at a phoneexchange is often modeled as a Poisson random variable. Assumethat on the av

Elza [17]

Answer:

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4 years ago

Which expression is equivalent to Negative 32 Superscript three-fifths?

Sidana [21]

Answer:

$-8$

Step-by-step explanation:

Given: $(-32)^{(\frac{3}{5}) }$

To choose: the correct option

Solution:

Power refers to a number of times, a number is multiplied by itself. Another name for power is exponent.

As per rule of exponents, $(a^m)^n=a^{mn}$

Here,

$(-32)=(-2)^5$

Therefore,

$(-32)^{(\frac{3}{5}) }=[(-2)^5]^{(\frac{3}{5}) }=(-2)^{5(\frac{3}{5}) }$

Here, $a=-2,m=5,n=\frac{3}{5}$

So,

$(-32)^{(\frac{3}{5}) }=[(-2)^5]^{(\frac{3}{5}) }=(-2)^{5(\frac{3}{5}) }=(-2)^3=-8$

8 0

3 years ago

Read 2 more answers

Researchers suspect that 18% of all high school students smoke at least one pack of cigarettes a day. At the local high school,

Nataliya [291]

Answer:

We conclude that 18% of all high school students smoke at least one pack of cigarettes a day.

Step-by-step explanation:

We are given that researchers suspect that 18% of all high school students smoke at least one pack of cigarettes a day.

At the local high school, a randomly selected sample of 300 students found that 50 students smoked at least one pack of cigarettes a day.

Let p = proportion of all high school students who smoke at least one pack of cigarettes a day.

So, Null Hypothesis, $H_0$ : p = 18% {means that 18% of all high school students smoke at least one pack of cigarettes a day}

Alternate Hypothesis, $H_A$ : p < 18% {means that less than 18% of all high school students smoke at least one pack of cigarettes a day}

The test statistics that would be used here is One-sample z -test for proportions because we are given with the proportions values;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students who smoked at least one pack of cigarettes a day = $\frac{50}{300}$ = 0.167

n = sample of students = 300

So, test statistics = $\frac{0.167-0.18}{\sqrt{\frac{0.167(1-0.167)}{300} } }$

= -0.604

The value of z test statistics is -0.604.

Also, P-value of the test statistics is given to us is 0.2743.

Since, the P-value of test statistics is more than the level of significance as 0.2743 > 0.025, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that 18% of all high school students smoke at least one pack of cigarettes a day.

6 0

3 years ago

There are 40 girls and 32 boys who want to participate in the relay race. If each team must have the same number of girls and bo

Oksi-84 [34.3K]

8 is the largest number that goes into both 32 and 40.

40/8 = 5
32/8 = 4

so there can be 8 teams, each consisting of 5 girls and 4 boys

6 0

3 years ago