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shepuryov [24]
3 years ago
10

Please look at the picture. Choices: A: 6 B: 10 C: 12 D: 14

Mathematics
1 answer:
tester [92]3 years ago
6 0
This difference would be 45 - 39, or 6 pages.
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Divide the combinations.<br><br> 60C3 / 15C3
Mariulka [41]
I hope you know what '!' means
2!=2
3!=6
4!=24
basicalkly times every natural number including and before that number


nCr=\frac{n!}{r!(n-r)!}
so
\frac{60C3}{15C3}=
\frac{ \frac{60!}{3!(60-3)!} }{ \frac{15!}{3!(15-3)!} }=
( \frac{60!}{3!(60-3)!})(\frac{3!(15-3)!}{15!})=
( \frac{60!}{3!(57)!})(\frac{3!(12)!}{15!})=
\frac{(60!)(3!)(12!)}{(3!)(57!)(15!)}=
\frac{(60!)(12!)}{(57!)(15!)}=
\frac{(60!)}{(57!)(15)(14)(13)}=
\frac{(60)(59)(58)}{(15)(14)(13)}=
\frac{(30)(59)(58)}{(15)(7)(13)}=
\frac{(6)(59)(58)}{(3)(7)(13)}=
\frac{6844}{91}
4 0
3 years ago
Read 2 more answers
The question goes like this:
Orlov [11]

Answer:

You have 90 pages left.

Step-by-step explanation:

1/4 × 120 = 30 pages read

Therefore

120- 30

=90 pages left to read

5 0
3 years ago
Read 2 more answers
Ab-0.5bab−0.5ba, b, minus, 0, point, 5, b when a=1a=1a, equals, 1 and b=5b=5b, equals, 5.
Vlad1618 [11]

Answer:

2.5

Step-by-step explanation:

5 0
3 years ago
A car's velocity is modeled by
Igoryamba

In accordance with the function <em>velocity</em>, the car will have a complete stop after 6 seconds.

<h3>When does the car stop?</h3>

Herein we have a function of the velocity of a car (v), in feet per second, in terms of time (t), in seconds. The car stops for t > 0 and v = 0, then we have the following expression:

0.5 · t² - 10.5 · t + 45 = 0

t² - 21 · t + 90 = 0

By the <em>quadratic</em> formula we get the following two roots: t₁ = 15, t₂ = 6. The <em>stopping</em> time is the <em>least</em> root of the <em>quadratic</em> equation, that is, the car will have a complete stop after 6 seconds.

To learn more on quadratic equations: brainly.com/question/2263981

#SPJ1

8 0
2 years ago
The depreciating value of a semi-truck can be modeled by y = Ao(0.85)x, where y is the remaining value of the semi, x is the tim
nata0808 [166]
We are given the equation
y = Ao (0.85)^x

Initially, at x = 0, the value of y is
y = Ao (0.85)^0
y = Ao

If the initial value was $65,000 at the same rate of depreciation, the equation would be
y = 65000 (0.85)^x
4 0
3 years ago
Read 2 more answers
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