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aalyn [17]
3 years ago
7

A) Deltoid: a = 89 mm; e = 110 mm; f = 78 mm; b= ? anybody know the answer??

Mathematics
1 answer:
bezimeni [28]3 years ago
3 0

Answer:

it should be 89 since A=89

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I really need some help .............
Effectus [21]

Answer:

61

Step-by-step explanation:

add the number of minutes for each day and then divide that number by the number of days

35+60+65+60+85 =305

305 / 5 = 61

8 0
3 years ago
Read 2 more answers
At a raffle, 1500 tickets are sold at $2 each. There are four prizes given for $500, $250, $150, and $75. You buy one ticket. Us
wolverine [178]

Answer:

<u>The expected value of every ticket is a loss of $ 1.35</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of tickets sold at the raffle = 1,500

Price of each ticket = $ 2

Total prizes = 1 * $ 500 + 1 * $ 250 + 1 * $ 150 + 1 * $ 75

2. Use a probability distribution table to calculate the expected value of your gain. Your expected value is_____ ?

Let's answer the question using a probability distribution for the gains, this way:

  • Probability of 1st prize of $ 498 (500 - ticket) = 1/1,500
  • Probability of 2nd prize of $ 248 (250 - ticket) = 1/1,500
  • Probability of 3rd prize of $ 148 (150 - ticket) = 1/1,500
  • Probability of 4th prize of $ 73 (75 - ticket) = 1/1,500
  • Probability of losing $ 2 (ticket) = 1,496/1,500

Now, we calculate the mean for all the tickets (winners and non-winners), this way:

Expected value = [(1,496 * -2) + (1 * 498) + (1 * 248) + ( 1 * 148) + ( 1 * 73)]/1,500

Expected value = [- 2,992 +498 + 248 + 148 + 73)/1,500

Expected value = -2,025/1,500 = - 1,35

<u>The expected value of every ticket is a loss of $ 1.35</u>

8 0
3 years ago
Lesson 13.3 Checkpoint
Arte-miy333 [17]

Answer:

a. LK = 4√3, JL= 4√6

b.  PQ = 10√3, RP = 5√3

Step-by-step explanation:

a. LK =4√3,

LK=KJ= 4√3

sin(45°) = opposite/hypotenuse

hypotenuse (JL)= opposite/sin 45° = 4√3/√2/2 = 8√3/√2 = 8√3√2/2 = 4√6

b.

cos 30° = adjacent/hypotenuse = QR/PQ = 15/PQ

cos 30° = 15/PQ

PQ = 15/cos 30° = 15/√3/2)= 30/√3 = 30√3/3 = 10√3

tan 30° = opposite/adjacent = RP/QR

√3/3 = RP/QR

√3/3 = RP/15

RP = √3*15/3 = 5√3

3 0
3 years ago
The polynomial p(x)=x^3-6x^2+32p(x)=x 3 −6x 2 +32p, left parenthesis, x, right parenthesis, equals, x, cubed, minus, 6, x, squar
Ray Of Light [21]

Answer:

(x-4)(x-4)(x+2)

Step-by-step explanation:

Given p(x) = x^3-6x^2+32 when it is divided by  x - 4, the quotient gives

x^2-2x-8

Q(x) = P(x)/d(x)

x^3-6x^2+32/x- 4  =  x^2-2x-8

Factorizing the quotient

x^2-2x-8

x^2-4x+2x-8

x(x-4)+2(x-4)

(x-4)(x+2)

Hence the polynomial as a product if linear terms is (x-4)(x-4)(x+2)

8 0
2 years ago
I need help ASAP people
nirvana33 [79]

Answer:

point D: (2, -4)

Step-by-step explanation:

5 0
3 years ago
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