Roberto overtakes Juanita at the rate of (7.7 mi)/(11 h) = 0.7 mi/h. This is the difference in their speeds. The sum of their speeds is (7.7 mi)/1 h) = 7.7 mi/h.
Roberto walks at the rate (7.7 + 0.7)/2 = 4.2 mi/h.
Juanita walks at the rate 4.2 - 0.7 = 3.5 mi/h.
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In a "sum and diference" problem, one solution is half the total of the sum and difference. If we let R and J be the respective speeds of Roberto and Juanita, we have
R + J = total speed
R - J = difference speed
Adding these two equations, we have
2R = (total speed + difference speed)
R = (total speed + difference speed)2 . . . . . as computed above
Answer:
pic?
Step-by-step explanation:
7<em>m</em> + 10<em>c</em> (is less than or equal to) 100.
<em>m</em> stands for months and <em>c</em> stands for CDs.
I hope this helps! :)
Answer:
0
Step-by-step explanation:
-2+3/-7+6
o/-1
0
as slope is y2-y1/
x2-x1
Answer:
give a little more explanation.
Step-by-step explanation:
