Question

I Need Help Pwease :-> ******************************

Answer 1

For this case we have that by definition, the perimeter of the trapezoid is given by the sum of its sides:

$p = 9 + 18 + 11 + 12\\p = 50$

So, the perimeter is 50ft

On the other hand, the area is given by:

$A = \frac {1} {2} (b_ {1} + b_ {2}) * h$

Where:

$b_ {1}:$ It is the largest base

$b_ {2}:$ It is the minor base

h: It's the height

Substituting the values:

$A = \frac {1} {2} (18 + 12) * 9\\A = \frac {1} {2} (30) * 9\\A = \frac {1} {2} (270)\\A = 135$

So, the area of the trapezoid is $135 \ ft ^ 2$

Answer:

the perimeter is 50ft

the area of the trapezoid is $135 \ ft ^ 2$

Answer 2

Answer:

Area: 135 ft^2

Perimeter: 50 ft

Step-by-step explanation:

area:

take the rectanle so length 12 x 9 = 108 so that is the length of the rectangle and now we need to find that of the triangle left over

subract 18 - 12 = 6 so that is the base of the trianle and we know the side length is 9 so plus it in A = (9)(6)/2

A = 54/2

A = 27

add 27 + 108 to get the total area

135

perimeter:

18 + 9 + 11 + 12 = 50