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3 years ago

I need help with this.

Mathematics

1 answer:

Nastasia [14]3 years ago

3 0

Answer: 7/64 or 0.109375

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There were 99 tulips in the field. Only 3/9 bloomed. How many tulips bloomed? How many did not bloom?

Ratling [72]

Answer: 33 tulips bloomed / 66 tulips did not bloom

Step-by-step explanation:

<h2>Given:</h2>

Total number of tulips = 99

Total number of tulips bloomed = 3/9 of total

<h2>Solve:</h2>

Step One: Find the number of tulips that bloomed

99 × (3/9) = 99 × (1/3) = 33 tulips

Step Two: Find the number of tulips that did not bloom

99 - 33 = 66 tulips

Hope this helps!! :)

Please let me know if you have any questions

6 0

3 years ago

The dot plot shows the number of hours, to the nearest

Hoochie [10]

Answer: Fifth grade mean: 4.67

Seventh grade mean: 3.46

Fifth grade median: 5

Seventh grade median: 3.5

Step-by-step explanation: I just did the question

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3 years ago

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Orlov [11]

Answer:

850- 475= 375 increase over 2 months.

375 ÷2= $187.50

4 0

2 years ago

Francine has a collection of 25 dolls. If 12% of the dolls are Monster High dolls, how many of the dolls are not Monster High Ex

Oksi-84 [34.3K]

9514 1404 393

Answer:

Step-by-step explanation:

The number of Monster High dolls is ...

12% × 25 = 3 . . . dolls

The others are not Monster High dolls. Their number is ...

25 -3 = 22 . . . not Monster High dolls

4 0

3 years ago

Factor the polynomial function over the complex numbers. f(x)=x^4-x^3-2x−4 Enter your answer in the box. f(x) = The answer is: (

Vladimir79 [104]

Answer:

Factors: $(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

Step-by-step explanation:

We are given a polynomial:

$f(x)=x^4-x^3-2x-4$

We have to factor the given polynomial into its complex factors.

The factorization can be done as follows:

$f(x)=x^4-x^3-2x-4 = 0\\x^4-x^3-2x-4 = 0\\x^4-4-x^3-2x=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^4-4)-(x^3+2x) = 0\\(x^2+2)(x^2-2)-x(x^2+2) = 0\\(x^2+2)(x^2-2-x) = 0\\(x^2+2)(x^2-x-2) = 0\\(x^2+2)(x^2-2x-+x-2) = 0\\(x^2+2)((x(x-2)+1(x-2))=0\\(x^2+2)(x+1)(x-2)=0\\\text{Identity: }a^2-b^2 = (a+b)(a-b)\\(x^2-(\sqrt{-2})^2)(x+1)(x-2)=0\\(x+i\sqrt2)(x-i\sqrt2)(x+1)(x-2)=0$

8 0

2 years ago

I need help with this.​

I need help with this.