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miv72 [106K]
3 years ago
10

What is the equation of the line that passes through the point (-4,6)(−4,6) and has a slope of -\frac{5}{4}−

Mathematics
1 answer:
AysviL [449]3 years ago
4 0

Answer:

5x + 4y - 4 = 0 is the given line equation.

Step-by-step explanation:

The slope m of the line is given as -\frac{5}{4}

The point  of the equation is (x0, y0) = (-4, 6)

Now, by POINT SLOPE formula of a  line:

Equation of  a line is :   ( y -y0) = m (x - x0)

Hence, the equation is (y - 6) = -\frac{5}{4} (x -(-4))

On further simplifying4(y - 6) = -5 (x + 4)\\or, 4y - 24 = -5x- 20 ,

⇒ 5x + 4y - 24 + 20 = 0

or, 5x + 4y - 4 = 0 is the given line equation.

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P+q=1 and pq=-20. What are the values of p and q?​
andrey2020 [161]

Answer:

Step-by-step explanation:

5, -4

5-4=1

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6 0
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Sam deposits $15,000.00 in an account that earns 3.2% simple interest. How much interest will his money earn in 1 year?
alex41 [277]
He will receive $480 in interest in the first year. 
4 0
4 years ago
Solve for x. Show each step of the solution x/16 = 3/8
Lina20 [59]

Answer:

x = 6

Step-by-step explanation:

x/16 = 3/8

Step 1: Cross-multiply.

x/16 = 3/8

x*(8) = (3)*(16)

8x = 48

Step 2: Divide both sides by 8.

8x/<em>8</em> = 48/<em>8</em>

<em>*Ta da!*</em>

x = 6

- Have a great day! -

7 0
2 years ago
Which of the following are true statements
Verizon [17]
I think it's 2,5,6 because a rational number is a number that can be put in a fraction.

Examples:

3/7 (3 over 7)

-2/5 (-2 over 5)

And 4, which can be put as 4/1 (4 over 1) in fraction form
3 0
3 years ago
Simplify tan9x-tan5x / 1+tan9xtan5x<br> (SHOW WORK)
Charra [1.4K]

Answer:

The simplest form is tan(4x)

Step-by-step explanation:

* Lets revise the identity of the compound angles

- tan(a+b)=\frac{tan(a)+tan(b)}{1-tan(a)tan(b)}

- tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}

* Lets solve the problem

- Let 9x = 5x + 4x

∴ tan(9x) = tan(5x + 4x)

- Use the rule of the compound angle

∵ \frac{tan(9x)-tan(5x)}{1+tan(9x)tan(5x)} ⇒ (1)

∵ tan(5x+4x)=\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)} ⇒ (2)

∵ tan(9x) = equation (2)

- Substitute (2) in (1)

∴ \frac{\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)}-tan(5x)}{1+(\frac{tan(5x)+tan(4x)}{1-tan(5x)tan(4x)})tan(5x)}

- Multiply up and down by (1 - tan(5x)tan(4x))

∴ \frac{tan(5x)+tan(4x)-tan(5x)[1-tan(5x)tan(4x)]}{1-tan(5x)tan(4x)+tan(5x)[tan(5x)+tan(4x)]}

- Simplify up and down

∴ \frac{tan(5x)+tan(4x)-tan(5x)+tan^{2}(5x)tan(4x)}{1-tan(5x)tan(4x)+tan^{2}(5x)+tan(5x)tan(4x) }

∴ \frac{tan(4x)+tan^{2}(5x)tan(4x)}{[1+tan^{2}(5x)]}

- Take tan(4x) as a common factor up

∴ \frac{tan(4x)[1+tan^{2}(5x)]}{[1+tan^{2}(5x)]}

- Cancel [1 + tan²(5x)] up and down

∴ The answer is tan(4x)

4 0
3 years ago
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