Question

What is the equation of the line that passes through the point (-4,6)(−4,6) and has a slope of -\frac{5}{4}−

Answer 1

Answer:

5x + 4y - 4 = 0 is the given line equation.

Step-by-step explanation:

The slope m of the line is given as $-\frac{5}{4}$

The point  of the equation is (x0, y0) = (-4, 6)

Now, by POINT SLOPE formula of a  line:

Equation of  a line is :   ( y -y0) = m (x - x0)

Hence, the equation is $(y - 6) = -\frac{5}{4} (x -(-4))$

On further simplifying$4(y - 6) = -5 (x + 4)\\or, 4y - 24 = -5x- 20$ ,

⇒ 5x + 4y - 24 + 20 = 0

or, 5x + 4y - 4 = 0 is the given line equation.