Answer:
Show ΔBCD ≅ ΔGFE, so ∠C ≅ ∠F. Base angle of an isosceles triangle are congruent, so ΔACF is isosceles.
Step-by-step explanation:
Informally, subtract DE from CE and DF. This will show CD ≅ EF.
Then ΔBCD ≅ ΔGFE by the HL theorem for right triangles.
Corresponding parts of congruent triangles are congruent, namely the angles C and F.
Since base angles of ΔACF are congruent, it is isosceles.
1/5 (c) since it goes up only one and then over 5
Answer:
d ≈ 1732 ft
Step-by-step explanation:
Angle of elevation = Angle of depression
Following this truth,
m∠PAQ (Angle of depression) = m∠APB (Angle of elevation) = 30°
By applying tangent rule in the given triangle ABP,
tan(30°) =
d = 1000√3
d = 1732.05
d ≈ 1732 ft
The answer is 9,520 I think