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sasho [114]
4 years ago
13

If f(x)=2x-6 and g(x)=x^3 what is (g f)(0)

Mathematics
1 answer:
kow [346]4 years ago
6 0
<h2>Hello!</h2>

The answer is:

(g\circ f)(0)=-216

<h2>Why?</h2>

To composite functions, we need to evaluate functions in another function(s), for example:

Given f(x) and g(x), if we want to calculate f(x) composite g(x), we need to evaluate g(x) into f(x).

So, we are given the functions:

f(x)=2x-6\\g(x)=x^{3}

And we are asked to calculate g(x) composite f(x), and then evaluate "x" to 0, so, calculating we have:

(g\circ f)(x)=g(f(x))\\\\(g\circ f)(x)=(2x-6)^{3}

Now that we have the composite function, we need to evaluate "x" equal to 0, so:

(g\circ f)(0)=(2x-6)^{3}\\\\(g\circ f)(0)=(2*(0)-6)^{3}=(0-6)^{3}=-6*-6*-6=-216

Hence, we have that:

(g\circ f)(0)=-216

Have a nice day!

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