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Pavlova-9 [17]
4 years ago
8

If M = N, the diameter of M = 148, and AB = 140, what is the length of NQ?

Mathematics
1 answer:
enyata [817]4 years ago
4 0

Answer:

NQ=24\ units

Step-by-step explanation:

we know that

Triangles ABM and CDN are congruent

so

CD=AB

AB=2AL ----> because the diameter divide the circle into two equal parts

CQ=AL=140/2=70 units

NC----> is the radius

NC=148/2=74 units ----> the radius is half the diameter

Applying Pythagoras Theorem find the value of NQ

NC^{2}=NQ^{2}+CQ^{2}

substitute the values

74^{2}=NQ^{2}+70^{2}

NQ^{2}=74^{2}-70^{2}

NQ^{2}=576

NQ=24\ units

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