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Talja [164]
4 years ago
11

he radius of a right circular cylinder is increasing at a rate of 7.5 inches per minute and the height is decreasing at a rate o

f 13.5 inches per minute. What is the rate of change of the surface area when the radius is 15.5 inches and the height is 33 inches
Mathematics
1 answer:
Pani-rosa [81]4 years ago
8 0

Answer:Rate of change of the surface area =876.85 square inches

Step-by-step explanation:

Surface area of a cylinder=2*pie*radius*height

Former radius and height are 8.0inches(15.5-7.5) and 46.5inches(33+13.5) respectively

New radius and height are 15.5inches and 33 inches respectively.(pie 22/7)

2*22*8*46.5=16368/7=2338.29

Also 2*22*15.5*33=22506/7=3215.14

Rate of change is 3215.14-2338.29=876.85inches

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Find the length of both arc AB and arc APB, where
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Find the dimensions of the rectangular corral split into 2 pens of the same size producing the greatest possible enclosed area g
Serjik [45]

Answer:Dimensions are of one corral is:

Length=50ft

Width= 37.5ft

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Step-by-step explanation:

Let L= length

Let w = width

There are 3 pieces of fencing: 3L + 4w =300

W = (300 -3L)/ 4 ....equation 1

Combined area of the corrals is given by:

A= L × 2w...eq2

Put eq1 into eq2

A= L ×2(300-3L) /4

A= 1/2 (300 -3 L)^2

A= -(3/2)L^2 + 150

Using -b/2a to solve for L in the quadratic equation

-150/2(3/2) = (150×2)/(2×3)

L = 50ft

W= 300-3(50)/4

W=150/4=37.5ft

Combined are=50×37.5=1875ft

3 0
4 years ago
What's the answer ????
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