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NeX [460]
4 years ago
13

Find the dimensions of the rectangular corral split into 2 pens of the same size producing the greatest possible enclosed area g

iven 300 feet of fencing. (Assume that the length is greater than or equal to the width.) ft length width ft Tutorial Additional Materials eBook Example Video
Mathematics
1 answer:
Serjik [45]4 years ago
3 0

Answer:Dimensions are of one corral is:

Length=50ft

Width= 37.5ft

Combined area=1875ft

Step-by-step explanation:

Let L= length

Let w = width

There are 3 pieces of fencing: 3L + 4w =300

W = (300 -3L)/ 4 ....equation 1

Combined area of the corrals is given by:

A= L × 2w...eq2

Put eq1 into eq2

A= L ×2(300-3L) /4

A= 1/2 (300 -3 L)^2

A= -(3/2)L^2 + 150

Using -b/2a to solve for L in the quadratic equation

-150/2(3/2) = (150×2)/(2×3)

L = 50ft

W= 300-3(50)/4

W=150/4=37.5ft

Combined are=50×37.5=1875ft

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#16 and #19 only <br> Please answer both as soon as possible.
Vlad1618 [11]

Answer:

1. it is not a direct variation because the value <em>k</em> is not kept throughout the ordered pairs

2. -a^5 - 2a³ + 2a², leading coefficient is -1

Step-by-step explanation:

1. to find the direct variation, we will use y/x = k with k representing our constant throughout the chart. if every value is equal to k, it is a direct variation

for this problem we will assume that the cup sizes are x and the cost is y

so the ordered pairs are (8, 0.90), (12, 1.35), (16, 1.80), and (24, 2.25)

.90/8 = 0.1125 <-- this is our <em>k</em> value for which every result has to be equal to

1.35/12 = 0.1125

1.80/12 = 0.1125

2.25/24 = 0.09375

since the value <em>k</em> was not kept throughout the ordered pairs, this is not a direct variation

2. the standard form of a polynomial is the exponents in descending order.

we have the following polynomial: 2a² - a^5 -2a³

to write it in standard form, we will go in descending order of the exponents. the largest exponent being first

-a^5 - 2a³ + 2a²

the leading coefficient of the polynomial is -1, as there is a negative sign in front of the newly formed polynomial

4 0
3 years ago
The amount of chlorine in a swimming pool varies directly with the volume of water. the pool has 2.5 milligrams of chlorine per
djverab [1.8K]

Answer:

Find out the  how much chlorine is in the pool .

To prove

As given

The amount of chlorine in a swimming pool varies directly with the volume of water.

The pool has 2.5 milligrams of chlorine per liter of water.

i.e

2.5 milligrams of chorine = 1 litre of water

There are 8000 gallons of water in the swimming pool.

As 1 gallons = 3.78541 litre (Approx)

Now convert 8000 gallons of water in litres.

8000 gallons = 8000 × 3.78541 litre

                      = 30283.28 litres

Now calculate chlorine in the pool for 30283.28 litres  of waters.

As

2.5 milligrams of chlorine = 1 litre of water

2.5 × 30283.28 milligrams of chlorine = 30283.28 litre of water

75708.2 milligrams of chlorine for 30283.28 litre of water .





3 0
3 years ago
Read 2 more answers
Helpppppppppppp 33points
Evgen [1.6K]

1st page: it is the fourth answer, y is less than or equal to 12

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3rd page: it is the first answer, x > -3

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3 years ago
The room measures 8 inches by 5 inches on the blueprint. If the scale on the blueprint is 1 inch by 4 feet, what is the actual a
larisa86 [58]
Hi there!

To solve this problem, we need to multiply each number by 4 ft.

8×4=32
5×4=20

Now, we films the area.

32×20 = 640

The area of the room is 640 feet squared.

Hope this helps!
3 0
3 years ago
A football team gains 7 yards in the first down then gains 2 yards in the second down. Then loses 4 yards in the third yard. Wha
Alinara [238K]

Answer: 5

Step-by-step explanation:

First we should do the first step: 7+2=9, The they lose 4 which then 9-4

which would equal 5

6 0
3 years ago
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