Question

PLEASE HELP ASAAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

Answer 1

Let i = sqrt(-1) which is the conventional notation to set up an imaginary number

The idea is to break up the radicand, aka stuff under the square root, to simplify

sqrt(-8) = sqrt(-1*4*2)

sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)

sqrt(-8) = i*2*sqrt(2)

sqrt(-8) = 2i*sqrt(2)

Answer is choice A