3 years ago

Help please!!! Question is in the picture

Mathematics

2 answers:

EastWind [94]3 years ago

8 0

I think it’s dababy

Nataly [62]3 years ago

6 0

I don’t really know where the Porche is

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A rectangle has a height of t^2+7t+6t

jek_recluse [69]

Answer:

$2t^3+15t^2+19t+6$

Step-by-step explanation:

Height of the Rectangle $=t^2+7t+6$

Width of the Rectangle $=2t+1$

Area of the Rectangle = Height X Width

$=(2t+1)(t^2+7t+6)\\=2t(t^2+7t+6)+1(t^2+7t+6)\\=2t^3+14t^2+12t+t^2+7t+6\\$Collect like terms\\=2t^3+14t^2+t^2+12t+7t+6\\Area=2t^3+15t^2+19t+6\\$

The area of the rectangle is $2t^3+15t^2+19t+6$

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3 years ago

Monique is painting a circle on the lunchroom wall. The radius of the circle is 3 feet

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1. find the center of the circle

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The total amount of water a tank can hold is 14 1/2 gallons. Raul wants to find out how many 1 1/4 gallon buckets of water can b

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Answer: $\frac{29}{2}$ ÷ $\frac{5}{4}$ , $\frac{29}{2}$ × $\frac{4}{5}$

Step-by-step explanation: Let me know if you need an explanation.

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Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)

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First, expand the terms inside the bracket you will get

$(( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) }$

$16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

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2 years ago

A farmer needs to enclose a section of land in the shape of a parallelogram by using one side of a barn for one side. the barn a

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The answer would be 9 feet.

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Help please!!! Question is in the picture​

Help please!!! Question is in the picture