Answer:
the endpoint not pH scale is 14
Answer:
Explanation:
A woman with type A blood (whose father was type O) meaning her genotype is AO mates with
Man that has type O blood (OO genotype)
Both are heterozygous for MN blood group and both also heterozygous for the FUT1 gene controlling the synthesis of the H substance (Hh)- which determines the expression of the A and B antigen.
Cross
A O M N H h
O AO OO M MM MN H HH Hh
O AO OO N MN NN h Hh hh
Type A- 1/2 O-1/2 type M- 1/4 MN-1/2 N- 1/4, type H- 3/4 h-1/4
Type A with M antigen:
1/2*1/4*3/4 = 3/32
Type A with M and N antigens:
1/2*1/2*3/4 = 3/16
Type A with N antigen:
1/2*1/4*3/4 = 3/32
Type O with M antigen:
1/2*1/4*3/4= 3/32
Type O with M and N antigens:
1/2*1/2*3/4 = 3/16
Type O with N antigen:
1/2*1/4*3/4 = 3/32.
The 3/4 value comes from the expression of Hh-3/4 (this determines if the A and B Angie will be expressed).
Answer:
16) 6 electrons
17) 6 protons
18) 6 neutrons
19) 4 electrons
20) 6
Explanation:
There are 6 electrons on the rings in total and 6 protons inside the nucleus. If you count the black cir les, there are 6 of them so there are 6 neutrons. Knowing that the inner ring can only hold 2 electrons the most, 6-2= 4. So there are 4 electrons on the outer ring. Knowing that you can get the atomic number based on the number of protons an atom have, the at pool mic number would be 6.
