CUMPLEIE

Mathematics

2 answers:

beks73 [17]3 years ago

6 0

the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake is 3.7

<u>Step-by-step explanation:</u>

Here we have , to find the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake . Let's find out:

We know that , Value of earthquake is given by formula

⇒ $M = Log(\frac{I_1}{I_0} )$ , Where M is magnitude of earthquake

$I_1$ is the measured magnitude of intensity of earthquake .

$I_0$ is the standard magnitude of intensity of earthquake .

According to question , $I_1 = 5011I_0$ , Hence

⇒ $M = Log(\frac{I_1}{I_0} )$

⇒ $M = Log(\frac{5011(I_0)}{I_0} )$

⇒ $M = Log(5011 )$

⇒ $M =3.69924$ { On rounding off we get }

⇒ $M =3.7$

Therefore , the magnitude of an earthquake that is 5,011 times more intense than a standard earthquake is 3.7

Blizzard [7]3 years ago

5 0

Answer:

3.7 on egde

Step-by-step explanation:

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