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Hatshy [7]
3 years ago
8

Margo wants a new carpet and a new wallpaper border for her bedroom. The room is 5.4 meters long and 4 7/8 meters wide. About ho

w many square yards of carpet will she need? About how many yards of wallpaper border will she need?
Mathematics
2 answers:
trasher [3.6K]3 years ago
8 0
I think you need to multiply rename
CaHeK987 [17]3 years ago
5 0
26.325m^2 of carpet. 17.8m of wallpaper. Convert to yards if you need to.
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V=2/3 ayuda porfavooooor
GalinKa [24]

Answer: answer is a

Step-by-step explanation:

3 0
1 year ago
Find the product (8/6n-4)(9n^2-4)
Leokris [45]

Answer:

4(3n+2) or 12n+8

Step-by-step explanation:

Given expression is:

(\frac{8}{6n-4})(9n^{2}-4)

The numerator of the fraction will be multiplied with 9n^2- 4

So, Multiplication will give us:

=\frac{8(9n^2-4)}{6n-4}

We can simplify the expression before multiplication.

The numerator will be broken down using the formula:

a^2 - b^2 = (a+b)(a-b)\\So,\\= \frac{8[(3n)^2 - (2)^2]}{6n-4}\\ = \frac{8(3n-2)(3n+2)}{6n-4}

We can take 2 as common factor from denominator

=\frac{8(3n-2)(3n+2)}{2(3n-2)}\\After\ cutting\\= 4(3n+2)

Hence the product is 4(3n+2) or 12n+8 ..

6 0
2 years ago
Four more than seven times a number is 12.” Write an equation that represents the statement. Then solve.
Leona [35]

7x + 4 = 12

7x = 12-4

7x = 8

x = 7/8

3 0
3 years ago
If a business borrows $20,000 and repays $29,200 in 4 years, what is the simple interest rate?
nekit [7.7K]

Answer:

11.5

Step-by-step explanation:

r= SI×100

_______

P×T

= 9200×100

_________

20000×4

= 920000

________

80000

4 0
3 years ago
The Cunninghams are moving across the country. Mr. Cunningham leaves 3 hours before Mrs. Cunningham. If he averages 40mph and sh
svp [43]
Recall your d = rt, distance = rate * time

now, if say, by the time they meet, Mr Cunningham has travelled "d" miles, that means Mrs Cunningham must also had travelled "d" miles as well.

However, he left 3 hours earlier, so by the time he travelled "d" miles, and took say "t" hours, for her it took 3 hour less, because she started driving 3 hours later, so, she's been on the road 3 hours less than Mr Cunningham, so by the time they meet, Mrs Cunningham has travelled then "t - 3" hours.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{Mr Cunningham}&d&40&t\\
\textit{Mrs Cunningham}&d&80&t-3
\end{array}
\\\\\\
\begin{cases}
\boxed{d}=40t\\
d=80(t-3)\\
----------\\
\boxed{40t}=80(t-3)
\end{cases}
\\\\\\
\cfrac{40t}{80}=t-3\implies \cfrac{t}{2}=t-3\implies t=2t-6\implies 6=2t-t
\\\\\\
6=t
5 0
3 years ago
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