Question

H(t)=-16(t-1)^2+16 What is the maximum height the ball reaches and how long does it take?

Answer 1

Given t = time and h = height

$h(t) = - 16(t - 1)^{2} + 16$

From the equation.

$y = a(x - h)^{2} + k$

h is the axis od symmetry

(h, k) is the vertex.

In the equation, h is 1 and k is 16.

So the maximum value is 16 at t = 1.

The ball reaches maximum at 16 and it takes t = 1 to reach the maximum point.