In this sequence d=10. Therefore, a24=188.
The smaller sector is 360-255=105 degree
it is 105/360 portion of the whole circle, and the area of the whole circle is πr², r is 14
so the area of the smaller sector is (105/360)*π*14²
run those numbers through your calculator, use 3.14 for π, you get 179.5
if you are looking for area of the larger sector, it would be
(255/360)*π*14²=435.94
Answer:
y = 56
Step-by-step explanation:
the midsegment SV is half the length of the side TU , that is
y - 9 = 
(y + 38) ← multiply both sides by 2 to clear the fraction
2y - 18 = y + 38 ( subtract y from both sides )
y - 18 = 38 ( add 18 to both sides )
y = 56
All the prime numbers betwemn 20 and 30 are 23 and 29
Yes because 13-5=8. not any other single number can be identified in the missing number
