Question

a tiny but horrible alien is standing at the top of the empire state building (which is 443443443 meters tall) and threatening to destroy the city of new york! a men in black agent is standing at ground level, 181818 meters across the street, aiming his laser gun at the alien. at what angle, in degrees, should the agent shoot his laser gun?

Answer 1

The angle for shooting laser gun should be 89.98°.

The vertical height where a tiny but horrible alien is standing is given as 443443443 meters. The horizontal distance of a men in black agent from building is given in the question as 181818 meters. So, let us assume the angle formed to be theta (θ).

Writing the formula for tan theta, that relates the given height and distance

Now, tan θ = vertical height ÷ horizontal distance

Keep the values in above mentioned equation of theta to find the angle.

tan θ = $\frac{443443443}{181818}$

Performing division to find the tan theta and subsequently calculate the angle

tan θ = 2438.94

θ = tan⁻¹ 2438.94

Calculating tan inverse to find the value of theta

θ = 89.98°

Therefore, the  angle for shooting laser gun by a men in black agent  should be 89.98°.

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