There are ways of picking 2 of the 10 available positions for a 0. 8 positions remain.
There are ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's
way of doing that.
So we have
The last expression has a more compact form in terms of the so-called multinomial coefficient,
v = 1/3Bh
Divide both sides by h.
v/h = 1/3B
Multiply both sides by 3.
3v/h = B
Answer:
Whereby circle P can be obtained from circle
O by applying the transformations of a translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4,
O is similar to
P
Step-by-step explanation:
The given center of the circle O = (-2, 7)
The radius of O, r₁ = 5
The given center of the circle P = (12, -1)
The radius of P, r₂ = 12
The similarity transformation to prove that O and
P are similar are;
a) Move circle O 14 units to the right and 8 units down to the point (12, -1)
b) Apply a scale of S.F. = r₂/r₁ = 12/5 = 2.4
Therefore, the radius of circle O is increased by 2.4
We then obtain O' with center at (12, -1) and radius r₃ = 2.4×5 = 12 which has the same center and radius as circle
P
∴ Circle P can be obtained from circle
O by applying similarity transformation of translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4,
O is similar to
P.