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eduard
3 years ago
6

Y=6x-11 -2x-3y=-7 solve each system of equation by substitution

Mathematics
1 answer:
Anit [1.1K]3 years ago
5 0

Answer:

(2, 1 )

Step-by-step explanation:

Given the 2 equations

y = 6x - 11 → (1)

- 2x - 3y = - 7 → (2)

Substitute y = 6x - 11 into (2)

- 2x - 3(6x - 11) = - 7 ← distribute and simplify left side

- 2x - 18x + 33 = - 7

- 20x + 33 = - 7 ( subtract 33 from both sides )

- 20x = - 40 ( divide both sides by - 20 )

x = 2

Substitute x = 2 into (1) for corresponding value of y

y = 6(2) - 11 = 12 - 11 = 1

Solution is (2, 1 )

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For the equation 3x - 5y = -3, what is the value of y when x is 1?<br><br> 6/5<br> -6/5<br> 5/6
babymother [125]

Answer:

\frac{-6}{5}

Step-by-step explanation:

3(1) - 5y = -3\\3 - 5y = -3\\-3 \\5y = -6\\/5 \\\\\frac{-6}{5}

           

3 0
3 years ago
Read 2 more answers
Can you please help me
Mandarinka [93]

Answer:  Attached.

Step-by-step explanation:

Either solve the equations directly, or graph them and look for the point of intersection.  

8 0
2 years ago
The length of a rectangular deck is five times it's width if the decks perimeter is 24 feet what is the decks area
miv72 [106K]

Answer:

20 square feet

Step-by-step explanation:

The length of a rectangular deck is five times it's width if the decks perimeter is 24 feet what is the decks area

Step 1

We find the Length and Width of the deck

Perimeter of a rectangle = 2L + 2W

The length of a rectangular deck is five times it's width

W = Width

L = Length = 5W

P = 24 feet

Perimeter = 2(5W) + 2W

24 = 10W + 2W

24 = 12 W

W = 24/12

W = 2 feet

Solving for L

L = 5W

L = 5 × 2 feet

L = 10 feet

Step 2

We find the area of the deck

Area of the deck(Rectangle) = Length × Width

= 10 feet × 2 feet

= 20 square feet

4 0
2 years ago
A line passes through the origin and the point (3,5). What is the slope of the line?
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3 years ago
Find, to four significant digits, the distance between the graphs of 2x-3y+4=0 and 2x-3y+15=0.
shepuryov [24]
In analytical geometry, we can find the linear distance between two parallel lines by determining the coefficients of the variables and the constants. The general equation for a linear equation is: Ax + By = C. 

Line 1: 2x - 3y = -4
Line 2: 2x - 3y = -15

In this case, A=2 and B=-3. The constants are C₁ = -4 and C₂ = -15. The distance follows this formula:

d = |C₁ - C₂|/(√(A²+B²)
d = |⁻4 - ⁻15|/(√(2²+⁻3²)
d = 3.051 units
4 0
3 years ago
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