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3 years ago

Find the cost of papering the four walls of a room 16m long, 12m broad and 8m high, with paper 2m wide at Rs 50 per metres.

1 answer:

6 0

$50 per square meter

the surface area of a rectangular prism with Legnth Widh and Height is
SA=2(LW+LH+WH)
so

L=16
W=12
H=8

SA=2(16*12+16*8+12*8)
SA=2(192+128+96)
SA=2(416)
SA=832 square meters

at 50 per square meter

so times 832 by 50 to get 41600

the cost is 41600 monies

You might be interested in

B 8 7 Find the length of "e" to the nearest tenth using the Pythagorean Theorem.

weeeeeb [17]

Answer:

≈ 10.63

Step-by-step explanation:

Pythagorean Theorem... Possibly the most easy theory in math once you understood it.

Here's the formula.

AB would be the hypothenuse

BC would be the opposite

CA would be the Adjacent.

But let's not make it complicated though, the question is actually quite easy.

You are asked to find AB, the hypothenuse.

The hypothenuse would be C.

BC and CA would be A and B.

It doesn't matter where are you going to place the numbers.

So,

= 113

Now we would have to square root 113 since

is an irrational number, and the question asks you to round ro the nearest tenth.

=10.63014581

≈ 10.63

Your answer would be 10.63

Hope this answer helped :)

5 0

3 years ago

Please answer this question!! 30 points and brainliest!

murzikaleks [220]

Answer:

D. 2x^2-7x.

Step-by-step explanation:

Lets write it out to make it easy to work with.

-x(-2x+7)

Multiply the -x out

2x^2-7x.

The answer is D

4 0

3 years ago

I need this solved ASAP please ratio 4:12 simplified.

saveliy_v [14]

I’m not 100% certain but i’m pretty sure 1:3 works

5 0

3 years ago

Read 2 more answers

I need to drag one into the box to match them

ioda

Answer:

54÷9 = 6 so for the second box is 6 hot dogs per person

54÷27= 2 third box is 2 hot dogs per person

54÷54= 1 fourth box is 1 hot dog per person

5 0

3 years ago

A study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school

nekit [7.7K]

Answer:

We conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

Step-by-step explanation:

We are given that a study by the National Athletic Trainers Association surveyed random samples of 1679 high school freshmen and 1366 high school seniors in Illinois.

Results showed that 34 of the freshmen and 24 of the seniors had used anabolic steroids.

Let $p_1$ = proportion of Illinois high school freshmen who have used anabolic steroids.

$p_2$ = proportion of Illinois high school seniors who have used anabolic steroids.

SO, Null Hypothesis, $H_0$ : $p_1=p_2$ {means that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

Alternate Hypothesis, $H_A$ : $p_1\neq p_2$ {means that there is a significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids}

The test statistics that would be used here Two-sample z test for proportions;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of high school freshmen who have used anabolic steroids = $\frac{34}{1679}$ = 0.0203

$\hat p_2$ = sample proportion of high school seniors who have used anabolic steroids = $\frac{24}{1366}$ = 0.0176

$n_1$ = sample of high school freshmen = 1679

$n_2$ = sample of high school seniors = 1366

So, the test statistics = $\frac{(0.0203-0.0176)-(0)}{\sqrt{\frac{0.0203(1-0.0203)}{1679}+\frac{0.0176(1-0.0176)}{1366} } }$

= 0.545

The value of z test statistics is 0.545.

Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that there is no significant difference in the proportion of all Illinois high school freshmen and seniors who have used anabolic steroids.

3 0

3 years ago