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attashe74 [19]
2 years ago
11

At hms 60% of the students voted in an election if there are 1,500 students how many voted

Mathematics
2 answers:
Nana76 [90]2 years ago
6 0

Answer:

900

Step-by-step explanation:

beks73 [17]2 years ago
4 0

Answer:

900 voted

Step-by-step explanation:

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x - 2y = 3 5x + 3y = 2 The lines whose equations are shown intersect at which point? (1, -1) (-1, 1) (0, 3/2)
gtnhenbr [62]
I would solve the first equation for x and then sub that value into x in the second equation.  That's the easiest way.  x - 2y = 3 solved for x is x = 2y+3.  Now sub that in for x in the second equation: 5(2y+3)+3y=2 and 10y + 15 + 3y = 2.  13y = -13, and y = -1.  Now sub that y value into either equation to solve for x: x = 2(-1) + 3 gives us an x value of x = 1.  Therefore, your solution to this system is (1, -1), first choice above.
4 0
3 years ago
6 cm 4 cm 10 cm What is the surface area of the figure? square centimeters ​
PSYCHO15rus [73]

Answer:

2 x 10 x 4 + (4 + 10) x 2 x 6 = 80 + 168 = 248

5 0
2 years ago
A number with one or more digits to the right of a decimal point is called a
stira [4]
It's called a decimal.
I hope it helps.
5 0
3 years ago
Read 2 more answers
Y = f(x) = 2^x
Virty [35]

Answer:

The value of f(x) when x=-1 is 0.5

Therefore f(-1)=0.5

Step-by-step explanation:

Given that y=f(x)=2^x

to find the f(x) when x=-1 :

That is to find f(-1)

Put x=-1 in the given function f(x)=2^x

f(-1)=2^{-1}

=\frac{1}{2}

=0.5

Therefore f(-1)=0.5

The value of f(x) when x=-1 is 0.5

3 0
3 years ago
The angle of elevation of the top of a pole as seen from a point 13 ft away from the base is double its angle of elevation as se
spayn [35]

The height of the pole above the level of the observer's eyes is 31.42 ft

Let the angle of elevation of the top of the pole from a point 47 ft away be α.

Let the angle of elevation of the top of the pole from the point 13 ft away be β.

Since the angle of elevation of a point 13 feet away is twice that from 47 ft away, we have that β = 2α.

If the height of the pole above the level of the observer's eye is h, we have that

tanβ = tan2α = h/13 and tanα = h/47

From trigonometric identities tan2α = 2tanα/(1 - tan²α)

Substituting the values of the variables into the equation, we have

tan2α = 2tanα/(1 - tan²α)

h/13 = 2h/47 ÷ [1 - (h/47)²]

Dividing through by h, we have

1/13 = 2/47 ÷ [1 - (h/47)²]

Cross-multiplying, we have

1/13 = 2/47 ÷ [1 - (h/47)²]

1 - (h/47)² = 2/47 × 13

1 - (h/47)² = 26/47

(h/47)² = 1 - 26/47

(h/47)² = (47 - 26)/47

(h/47)² = 21/47

Taking square-root of both sides, we have

h/47 = √(21/47)

Cross-multiplyng, we have

h = √(21/47) × 47

h = √(21 × 47)

h = √987

h = 31.42 ft

The height of the pole above the level of the observer's eyes is 31.42 ft

Learn more about height of a pole here:

brainly.com/question/10375496

4 0
2 years ago
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